Question detail

Describe how the rate of a chemical reaction changes with temperature, and explain why this occurs.

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Question

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Style

Topic

A-level practical endorsement and required practical activities

Question

Describe how the rate of a chemical reaction changes with temperature, and explain why this occurs.

Answer

The rate of a chemical reaction generally increases with temperature. This is because higher temperatures provide reactant particles with more kinetic energy, leading to more frequent and energetic collisions between them, which increases the likelihood of successful reactions. This answer is anchored to A-level required practical activities.

Explanation

The rate of a chemical reaction generally increases with temperature. This is because higher temperatures provide reactant particles with more kinetic energy, leading to more frequent and energetic collisions between them, which increases the likelihood of successful reactions. is the best answer because it directly supports the AQA A-Level Chemistry objective to required practical 3: investigate how rate changes with temperature. This reasoning is anchored to A-level required practical activities in A-level practical endorsement and required practical activities, and it separates required practical from similar A-Level ideas rather than relying on a vague recall statement. Other options are weaker if they use the wrong evidence, calculation, mechanism, observation, unit, or conclusion for this subtopic.

Common mistake

Temperature and Rate of Reaction

Students often incorrectly assume that increasing temperature will always double the rate of reaction without considering the specific reaction conditions.

To accurately determine how rate changes with temperature, use the Arrhenius equation: k = Ae^(-Ea/RT). Substitute the activation energy (Ea), the universal gas constant (R), and the temperature (T in Kelvin) to find the rate constant (k). For example, if Ea = 50 kJ/mol, R = 8.314 J/(mol·K), and T = 298 K, then: 1. Convert Ea to J: 50 kJ/mol = 50000 J/mol. 2. Substitute: k = Ae^(-50000/(8.314*298)). 3. Calculate: k = Ae^(-20.12). 4. The final answer will give the rate constant k in appropriate units, showing how the rate of reaction changes with temperature. Keep the correction anchored to A-level required practical activities and the objective: Required practical 3: investigate how rate changes with temperature.

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