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If a solid cylinder has a moment of inertia given by I = 0.5 * m * r^2, what happens to the moment of inertia if the radius is tripled?

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MCQ

Type

practice

Style

Topic

Rotational dynamics

Exam-style question

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If a solid cylinder has a moment of inertia given by I = 0.5 * m * r^2, what happens to the moment of inertia if the radius is tripled?.

  1. A.It remains the same.
  2. B.It triples.
  3. C.It increases by a factor of nine.
  4. D.It decreases by a factor of three.

Model answer

What a good answer should say

  • It increases by a factor of nine.

Explanation

Why this works

Using the formula I = 0.5 * m * r^2, if the radius (r) is tripled, the moment of inertia becomes I = 0.5 * m * (3r)^2 = 0.5 * m * 9r^2, which shows it increases by a factor of nine.

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