Exam-style question
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If a torque of 10 N·m is applied to a solid cylinder with a moment of inertia of 2 kg·m², what is the angular acceleration produced?.
- A.5 rad s⁻²
- B.2 rad s⁻²
- C.10 rad s⁻²
- D.0.2 rad s⁻²
Model answer
What a good answer should say
- 5 rad s⁻²
Explanation
Why this works
Using τ = Iα, rearrange to α = τ/I. Substituting τ = 10 N·m and I = 2 kg·m² gives α = 10/2 = 5 rad s⁻².
This shows how a larger moment of inertia reduces the angular acceleration for a given torque.
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