Exam-style question
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If a capacitor has a capacitance of 2 F and is charged to 8 V, what is the energy stored in the capacitor?.
- A.8 J
- B.16 J
- C.32 J
- D.4 J
Model answer
What a good answer should say
- 8 J
Explanation
Why this works
The energy stored in a capacitor is given by the formula E = 0.5 * C * V^2. Substituting the values: E = 0.5 * 2 F * (8 V)^2 = 0.5 * 2 * 64 = 64 J.
Therefore, the energy stored is 64 joules.
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