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In simple harmonic motion (SHM), the acceleration of an object is directly proportional to its displacement from the equilibrium position. What is the relationship between acceleration (a), displacement (x), and the constant (k)?

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MCQ

Type

practice

Style

Topic

Periodic motion

Exam-style question

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In simple harmonic motion (SHM), the acceleration of an object is directly proportional to its displacement from the equilibrium position. What is the relationship between acceleration (a), displacement (x), and the constant (k)?.

  1. A.a = -kx
  2. B.a = kx
  3. C.a = k/x
  4. D.a = -k/x

Model answer

What a good answer should say

  • a = -kx

Explanation

Why this works

The correct relationship is a = -kx, which shows that acceleration is proportional to displacement and directed towards the equilibrium position, indicating restoring force in SHM.

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