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Using the equation KE = (3/2)kT, calculate the average kinetic energy of a gas molecule at a temperature of 300 K. (Use k = 1.38 x 10^-23 J/K) Scenario focus: use ideal gas reasoning in a distinct A-Level Physics context and identify the relevant physical quantity before choosing the answer.

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exam_style

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Topic

Thermal physics

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Using the equation KE = (3/2)kT, calculate the average kinetic energy of a gas molecule at a temperature of 300 K. (Use k = 1.38 x 10^-23 J/K) Scenario focus: use ideal gas reasoning in a distinct A-Level Physics context and identify the relevant physical quantity before choosing the answer.

Model answer

What a good answer should say

  • The average kinetic energy of the gas molecule is 6.21 x 10^-21 J.

Explanation

Why this works

The correct answer is The average kinetic energy of the gas molecule is 6.21 x 10^-21 J.. This option is correct for Thermal physics because it applies the ideal gas reasoning idea in the stem and keeps the relevant quantity, unit, and physical conclusion together.

The alternatives either use a neighbouring formula, omit a required variable, or describe a different physical situation.

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