Exam-style question
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If a 3 kg object absorbs 6000 J of thermal energy and its temperature increases by 5 °C, what is the specific heat capacity of the object?.
- A.400 J/kg°C
- B.600 J/kg°C
- C.800 J/kg°C
- D.1000 J/kg°C
Model answer
What a good answer should say
- 400 J/kg°C
Explanation
Why this works
Using the formula E = m x c x Δθ, we rearrange to find c = E / (m x Δθ). Substituting E = 6000 J, m = 3 kg, and Δθ = 5 °C: c = 6000 / (3 x 5) = 400 J/kg°C.
Therefore, the specific heat capacity is 400 J/kg°C.
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