Exam-style question
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Calculate the energy of a photon emitted when an electron transitions from the n=3 to n=2 energy level in a hydrogen atom. Use the formula E = -13.6 eV (1/n_final^2 - 1/n_initial^2).
- A.1.89 eV
- B.3.40 eV
- C.0.85 eV
- D.5.13 eV
Model answer
What a good answer should say
- 1.89 eV
Explanation
Why this works
The correct option is 1.89 eV because it represents the energy difference between the two energy levels calculated using the formula for photon energy in hydrogen.
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