Exam-style question
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An electron transitions from the n=4 to n=1 energy level in a hydrogen atom. Calculate the energy of the emitted photon. Use E = -13.6 eV (1/n_final^2 - 1/n_initial^2).
- A.10.20 eV
- B.12.09 eV
- C.13.60 eV
- D.1.51 eV
Model answer
What a good answer should say
- 12.09 eV
Explanation
Why this works
The correct option is 12.09 eV, which is the energy difference calculated for the transition from n=4 to n=1 using the energy level formula.
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