Exam-style question
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Calculate the energy of a photon emitted when an electron transitions from n=5 to n=3 in a hydrogen atom. Use E = -13.6 eV (1/n_final^2 - 1/n_initial^2).
- A.0.54 eV
- B.1.51 eV
- C.2.55 eV
- D.0.66 eV
Model answer
What a good answer should say
- 0.66 eV
Explanation
Why this works
The correct option is 0.66 eV, calculated from the energy difference between the two levels using the provided formula.
Common mistake
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