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A hydrogen atom emits an infrared photon when an electron drops from n=7 to n=4. Use the energy-level equation to calculate the photon energy, then link the smaller transition energy to the longer wavelength region.

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MCQ

Type

practice

Style

Topic

Electromagnetic radiation and quantum phenomena

Exam-style question

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A hydrogen atom emits an infrared photon when an electron drops from n=7 to n=4. Use the energy-level equation to calculate the photon energy, then link the smaller transition energy to the longer wavelength region.

  1. A.1.89 eV
  2. B.2.55 eV
  3. C.3.40 eV
  4. D.5.13 eV

Model answer

What a good answer should say

  • 2.55 eV

Explanation

Why this works

The transition from n=7 to n=4 has a smaller energy gap than drops to n=1 or n=2. The calculated emitted photon energy is 2.55 eV, so the answer should connect the lower energy change with a longer-wavelength photon rather than only quoting the number.

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