Exam-style question
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Calculate the energy of a photon emitted when an electron transitions from the n=3 to the n=2 energy level in a hydrogen atom. Use the formula E = hf, where h = 6.63 x 10^-34 J·s and f = 4.57 x 10^14 Hz.
Model answer
What a good answer should say
- The energy of the photon is 3.03 x 10^-19 J.
Explanation
Why this works
Using the formula E = hf, we substitute h and f to find the energy of the emitted photon. This calculation tests the student's ability to apply the formula in a practical context.
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