Exam-style question
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What is the de Broglie wavelength of an electron with a momentum of 3.2 x 10^-24 kg m/s?.
- A.2.06 x 10^-10 m
- B.1.24 x 10^-10 m
- C.4.00 x 10^-10 m
- D.9.80 x 10^-10 m
Model answer
What a good answer should say
- 2.06 x 10^-10 m
Explanation
Why this works
The de Broglie wavelength (λ) is calculated using the formula λ = h / p, where h is Planck's constant (6.63 x 10^-34 J s) and p is momentum. Substituting gives λ = 6.63 x 10^-34 J s / (3.2 x 10^-24 kg m/s) = 2.06 x 10^-10 m.
This shows the wave nature of the electron.
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