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If a spaceship travels at 0.6c relative to Earth, how does its clock compare to Earth's clock?

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MCQ

Type

practice

Style

Topic

Special relativity

Exam-style question

Try this first

If a spaceship travels at 0.6c relative to Earth, how does its clock compare to Earth's clock?.

  1. A.It ticks 1.25 times faster.
  2. B.It ticks 1.25 times slower.
  3. C.It ticks at the same rate.
  4. D.It ticks 0.8 times slower.

Model answer

What a good answer should say

  • It ticks 1.25 times slower.

Explanation

Why this works

Formula: Δt = γ Δτ. Substitution: v = 0.6c → γ = 1/√(1–0.36) ≈ 1.25.

Working: Δt = 1.25 Δτ. Answer: the spaceship’s clock takes 1.25 times longer to tick one second, so it runs slower.

Units/conclusion: The spaceship’s clock runs 1.25 times slower than Earth’s clock.

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