Exam-style question
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What is the critical angle for a medium with a refractive index of 1.75 when light travels to air?.
- A.34.2°
- B.42.0°
- C.48.6°
- D.56.3°
Model answer
What a good answer should say
- 34.2°
Explanation
Why this works
To find the critical angle, use the formula: critical angle = sin⁻¹(1/n). For n = 1.75, we have sin⁻¹(1/1.75) = 34.2°.
This angle indicates the limit for total internal reflection when light exits the medium.
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