Question detail
Chemical changes case 014 reactivity-evidence. A student uses the reactivity series to justify an observation. Which option is best? Focus on oxide ions losing electrons the anode form oxygen in Using electrolysis to extract metals, not on a neighbouring Unit 4.4 reaction idea.
Try the question, check the answer, then read the explanation to understand the curriculum point.
At a glance
MCQ
Type
practice
Style
Topic
Electrolysis
Question
- A. Chemical changes case 014 reactivity-evidence: Uses the relative reactivity order to predict the change for oxide ions losing electrons the anode form oxygen
- B. Chemical changes case 014 reactivity-evidence: Chooses the product by memorising a colour instead of the series (Using electrolysis to extract metals)
- C. Chemical changes case 014 reactivity-evidence: Says any metal can displace any other metal ion (oxide ions losing electrons the anode form oxygen)
- D. Chemical changes case 014 reactivity-evidence: Ignores whether the reacting substance is more or less reactive (Electrolysis)
Answer
The correct option is Chemical changes case 014 reactivity-evidence: Uses the relative reactivity order to predict the change for oxide ions losing electrons the anode form oxygen.
Explanation
The correct option is Chemical changes case 014 reactivity-evidence: Uses the relative reactivity order to predict the change for oxide ions losing electrons the anode form oxygen. It is correct because it directly supports the approved learning objective to describe oxide ions losing electrons at the anode to form oxygen in Using electrolysis to extract metals. The other options are incorrect because they blur a Unit 4.4 concept boundary: acid versus alkali versus base, oxidation versus reduction, displacement versus reduction, electrolysis versus electroplating, anode versus cathode, positive versus negative ions, oxidation state versus ionic charge, or strong acid versus concentrated acid.
Common mistake
Confusing Oxide Ion Behavior
Students often state that oxide ions gain electrons at the anode instead of losing them.
Remember that oxidation occurs at the anode, where negative ions like oxide lose electrons to form oxygen.
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