Question detail

For Conservation of mass and balanced chemical equations, which option best supports this Unit 4.3 objective: Explain that the mass of the products equals the mass of the reactants in a chemical reaction?

Try the question, check the answer, then read the explanation to understand the curriculum point.

At a glance

MCQ

Type

practice

Style

Topic

Chemical measurements, conservation of mass and the quantitative interpretation of chemical equations

Question

  1. A. To show the number of atoms of each element in a molecule.
  2. B. To indicate the total mass of the compound.
  3. C. To represent the state of matter.
  4. D. To balance the equation.

Answer

The correct option is To show the number of atoms of each element in a molecule..

Explanation

The correct option is To show the number of atoms of each element in a molecule.. To show the number of atoms of each element in a molecule. is correct because it directly supports the approved learning objective to explain that the mass of the products equals the mass of the reactants in a chemical reaction. The reasoning belongs to Conservation of mass and balanced chemical equations within Chemical measurements, conservation of mass and the quantitative interpretation of chemical equations, so it should not be confused with nearby quantitative ideas such as mass, moles, concentration, yield, atom economy, or gas volume unless those are named in the objective. Use the focus term reactant to keep the answer aligned with AQA GCSE Chemistry 8462 Unit 4.3. The other options are weaker because they either use the wrong formula, the wrong unit, a vague relationship, or the wrong quantitative context.

Common mistake

Mass Misunderstanding

Students often think that the mass of products can differ from the mass of reactants in a chemical reaction.

Emphasize that according to the law of conservation of mass, the total mass of reactants must equal the total mass of products in a closed system.

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understanding MCQ 4: reactants in a chemical reaction. | Chemical… | ExamCompanion