Question detail
In a reaction, 5 g of reactant X (Mr = 40 g/mol) and 10 g of reactant Y (Mr = 20 g/mol) are used. Determine the limiting reactant if the balanced equation shows a 1:2 ratio of X to Y.
Try the question, check the answer, then read the explanation to understand the curriculum point.
At a glance
Question
Type
exam_style
Style
Topic
Use of amount of substance in relation to masses of pure substances
Question
In a reaction, 5 g of reactant X (Mr = 40 g/mol) and 10 g of reactant Y (Mr = 20 g/mol) are used. Determine the limiting reactant if the balanced equation shows a 1:2 ratio of X to Y.
Answer
The answer is Reactant X is the limiting reactant.
Explanation
This uses Limiting Reactant Ratio because the objective is about (HT only) Define the limiting reactant as the reactant that is completely used up in a reaction. The reasoning belongs to Limiting reactants (HT only) within Use of amount of substance in relation to masses of pure substances, so it should not be confused with nearby quantitative ideas such as mass, moles, concentration, yield, atom economy, or gas volume unless those are named in the objective. Use the focus term HT only to keep the answer aligned with AQA GCSE Chemistry 8462 Unit 4.3.
Common mistake
Confusing Limiting Reactant
Students often confuse the limiting reactant with the reactant present in excess, thinking both are the same.
Remember that the limiting reactant is the one that gets completely used up, while the excess reactant remains after the reaction.
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