Question detail
For Concentrations in mol/dm3 and titration calculations, which exam wording answer best supports this Unit 4.3 objective: (chemistry only) (HT only) Calculate concentration in mol/dm3 from mass of solute and volume?
Try the question, check the answer, then read the explanation to understand the curriculum point.
At a glance
MCQ
Type
practice
Style
Topic
Using concentrations of solutions in mol/dm3 (chemistry only) (HT only)
Question
- A. 0.34 mol/dm3 - correct exam wording for HT only
- B. Wrong exam wording: confuses HT only with a nearby Unit 4.3 idea
- C. Wrong unit check: uses the wrong unit for Concentrations in mol/dm3 and titration calculations
- D. Wrong calculation link: does not support (chemistry only) (HT only) Calculate concentration in mol/dm3 from mass of solute and volume
Answer
The correct option is 0.34 mol/dm3 - correct exam wording for HT only. The calculated answer is 0.34 mol/dm3.
Explanation
The correct option is 0.34 mol/dm3 - correct exam wording for HT only. This uses Concentration in mol/dm3 because the objective is about (chemistry only) (HT only) Calculate concentration in mol/dm3 from mass of solute and volume. This exam wording variant asks students to separate HT only from similar Unit 4.3 calculation steps. The reasoning belongs to Concentrations in mol/dm3 and titration calculations within Using concentrations of solutions in mol/dm3 (chemistry only) (HT only), so it should not be confused with nearby quantitative ideas such as mass, moles, concentration, yield, atom economy, or gas volume unless those are named in the objective. Use the focus term HT only to keep the answer aligned with AQA GCSE Chemistry 8462 Unit 4.3. The other options are weaker because they either use the wrong formula, the wrong unit, a vague relationship, or the wrong quantitative context.
Common mistake
Incorrect Unit Conversion
Students often forget to convert volumes from cm3 to dm3 when calculating concentration in mol/dm3.
Always convert cm3 to dm3 by dividing the volume in cm3 by 1000 before using it in concentration calculations.
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