Question detail

What mass of sodium hydroxide (NaOH) is needed to prepare 0.2 dm3 of a 1 mol/dm3 solution? (Mr of NaOH = 40 g/mol)

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At a glance

MCQ

Type

practice

Style

Topic

Using concentrations of solutions in mol/dm3 (chemistry only) (HT only)

Question

  1. A. 8 g
  2. B. 4 g
  3. C. 2 g
  4. D. 10 g

Answer

8 g

Explanation

Calculate moles needed: moles = concentration x volume = 1 mol/dm3 x 0.2 dm3 = 0.2 mol. Then, mass = moles x Mr = 0.2 mol x 40 g/mol = 8 g.

Common mistake

Volume Conversion Mistake

Students often forget to convert cm3 to dm3 when calculating concentration, leading to incorrect results.

Always remember to convert volumes from cm3 to dm3 by dividing by 1000 before using them in concentration calculations.

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