Question detail
What mass of sodium hydroxide (NaOH) is needed to prepare 0.2 dm3 of a 1 mol/dm3 solution? (Mr of NaOH = 40 g/mol)
Try the question, check the answer, then read the explanation to understand the curriculum point.
At a glance
MCQ
Type
practice
Style
Topic
Using concentrations of solutions in mol/dm3 (chemistry only) (HT only)
Question
- A. 8 g
- B. 4 g
- C. 2 g
- D. 10 g
Answer
8 g
Explanation
Calculate moles needed: moles = concentration x volume = 1 mol/dm3 x 0.2 dm3 = 0.2 mol. Then, mass = moles x Mr = 0.2 mol x 40 g/mol = 8 g.
Common mistake
Volume Conversion Mistake
Students often forget to convert cm3 to dm3 when calculating concentration, leading to incorrect results.
Always remember to convert volumes from cm3 to dm3 by dividing by 1000 before using them in concentration calculations.
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