Question detail
A sample has a count rate of 320 counts per minute. If it undergoes 2 half-lives, what will be the new count rate? Use the radiation dose context to keep Half-lives and the random nature of radioactive decay distinct from nearby atomic and nuclear radiation ideas.
Try the question, check the answer, then read the explanation to understand the curriculum point.
At a glance
MCQ
Type
practice
Style
Topic
Atoms and nuclear radiation
Question
- A. 80 counts per minute (halflives and the random nature)
- B. 160 counts per minute (halflives and the random nature)
- C. 320 counts per minute (halflives and the random nature)
- D. 640 counts per minute (halflives and the random nature)
Answer
The correct answer is 80 counts per minute (halflives and the random nature).
Explanation
The correct answer is 80 counts per minute (halflives and the random nature). It supports the learning objective: Calculate the count rate or activity remaining after a whole number of half-lives.. The correct answer is 80 counts per minute (halflives and the random nature). It directly supports the learning objective: Calculate the count rate or activity remaining after a whole number of half-lives.. In Half-lives and the random nature of radioactive decay, this is the best option because it matches the specific radiation dose context; the other options mix up nearby ideas such as activity, count rate, isotope notation, radiation type, or nuclear-equation changes.
Common mistake
Misunderstanding Half-Life Calculations
Students often confuse the concept of half-life with the total decay time, leading to incorrect calculations of remaining count rate or activity.
To accurately calculate the remaining count rate after a number of half-lives, remember that each half-life reduces the count rate by half. Use the formula: remaining count rate = initial count rate × (0.5)^n, where n is the number of half-lives.
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