Question detail
For a spring with k = 250 N/m compressed by 0.3 m, which working correctly finds the elastic potential energy?
Try the question, check the answer, then read the explanation to understand the curriculum point.
At a glance
MCQ
Type
practice
Style
Topic
Energy changes in a system, and the ways energy is stored before and after such changes
Question
- A. Ee = 0.5 � 250 � 0.3� = 11.25 J
- B. Ee = 250 � 0.3 = 75 J
- C. Ee = 0.5 � 250 � 0.3 = 37.5 J
- D. Ee = 250 � 0.3 = 833 J
Answer
Ee = 0.5 � 250 � 0.3� = 11.25 J
Explanation
The correct option is "Ee = 0.5 � 250 � 0.3� = 11.25 J". It is right because elastic potential energy uses Ee = 0.5ke�, so the extension must be squared before multiplying by half the spring constant.
Common mistake
Misunderstanding Elastic Potential Energy Calculation
Students often confuse the elastic potential energy formula Ee = 0.5 x k x e^2 by misidentifying the spring constant (k) and extension (e).
Ensure to correctly identify k as the spring constant in N/m and e as the extension in meters before substituting values into the formula.
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