Question detail

A different spring has k = 80 N/m and extension e = 0.7 m. Which substitution keeps the elastic energy equation correct?

Try the question, check the answer, then read the explanation to understand the curriculum point.

At a glance

MCQ

Type

practice

Style

Topic

Energy changes in a system, and the ways energy is stored before and after such changes

Question

  1. A. Ee = 0.5 � 80 � 0.7� = 19.6 J
  2. B. Ee = 80 � 0.7� = 39.2 J
  3. C. Ee = 0.5 � 80 � 0.7 = 28 J
  4. D. Ee = 80 � 0.7 = 114 J

Answer

Ee = 0.5 � 80 � 0.7� = 19.6 J

Explanation

The correct option is "Ee = 0.5 � 80 � 0.7� = 19.6 J". It is right because the elastic potential energy formula includes both the half factor and the squared extension.

Common mistake

Misunderstanding Elastic Potential Energy Calculation

Students often confuse the elastic potential energy formula Ee = 0.5 x k x e^2 by misidentifying the spring constant (k) and extension (e).

Ensure to correctly identify k as the spring constant in N/m and e as the extension in meters before substituting values into the formula.

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