A spring with a spring constant of 120 N m⁻¹ is stretched 0.08 m from its relaxed length. Calculate the elastic potential energy stored in the spring Explain your answer using Elastic potential energy and elastic potential energy.

The elastic potential energy is 0.5 × 120 N m⁻¹ × (0.08 m)² = 0.384 J. The spring stores 0.384 J of elastic potential energy.

A strong answer should address apply MS 3b and MS 3c skills when calculating elastic potential energy directly. Use the context of Elastic potential energy within Forces and elasticity, then state the relevant forces or motion reasoning with units where needed. The answer is correct when it names the key physics quantity, keeps elastic and plastic deformation distinct, and links the conclusion back to the approved learning objective.