Question detail

Forces and elasticity scenario: weight and normal contact force act on one object. Which answer best addresses Hooke's law and spring constant and the objective to calculate spring constant from force and extension?

Try the question, check the answer, then read the explanation to understand the curriculum point.

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At a glance

MCQ

Type

practice

Style

Topic

Forces and elasticity

Question

A. In the book on table scenario, apply force to calculate spring constant from force and extension while keeping elastic versus plastic deformation separate.
B. In the book on table scenario, mix up elastic versus plastic deformation and ignore force.
C. Use a general revision statement without applying Hooke's law and spring constant to the situation.
D. Choose a different forces topic instead of explaining calculate spring constant from force and extension.

Answer

The correct answer is: In the book on table scenario, apply force to calculate spring constant from force and extension while keeping elastic versus plastic deformation separate.

Explanation

The correct option is In the book on table scenario, apply force to calculate spring constant from force and extension while keeping elastic versus plastic deformation separate.. It is correct because the scenario says weight and normal contact force act on one object, which must be interpreted through Hooke's law and spring constant. This directly supports the learning objective to calculate spring constant from force and extension. Use values 7, 10, and 13 only if the question asks for a calculation. The answer earns credit by naming the relevant force or motion quantity, using units when needed, and avoiding the boundary error elastic versus plastic deformation.

Common mistake

Common Mistake in Spring Constant Calculation

Students often confuse the units of spring constant, using N instead of N/m.

Remember that the spring constant is defined as the force per unit extension, so it must be expressed in newtons per metre (N/m).

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