Question detail

If a spring has a spring constant of 200 N/m and is extended by 0.5 m, what is the force applied to the spring?

Try the question, check the answer, then read the explanation to understand the curriculum point.

At a glance

MCQ

Type

practice

Style

Topic

Forces and elasticity

Question

  1. A. 100 N
  2. B. 200 N
  3. C. 300 N
  4. D. 400 N

Answer

100 N

Explanation

Using Hooke's law (F = k * e), where F is the force, k is the spring constant (200 N/m), and e is the extension (0.5 m), the force is calculated as 200 N/m * 0.5 m = 100 N.

Common mistake

Misunderstanding Proportionality

Students often confuse the relationship between force and extension, thinking that extension is proportional to force beyond the limit of proportionality.

Remember that extension is only directly proportional to force up to the limit of proportionality; beyond this point, the relationship changes.

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application MCQ 5: to the limit of proportionality. | Forces and… | ExamCompanion