Question detail
Momentum scenario: air resistance changes until terminal velocity is reached. Which answer best addresses Momentum and conservation of momentum (HT only) and the objective to (HT only) Calculate velocity from momentum and mass?
Try the question, check the answer, then read the explanation to understand the curriculum point.
At a glance
MCQ
Type
practice
Style
Topic
Momentum
Question
- A. In the parachutist scenario, apply momentum to (HT only) Calculate velocity from momentum and mass while keeping mass versus weight separate.
- B. In the parachutist scenario, mix up mass versus weight and ignore momentum.
- C. Use a general revision statement without applying Momentum and conservation of momentum (HT only) to the situation.
- D. Choose a different forces topic instead of explaining (HT only) Calculate velocity from momentum and mass.
Answer
The correct answer is: In the parachutist scenario, apply momentum to (HT only) Calculate velocity from momentum and mass while keeping mass versus weight separate.
Explanation
The correct option is In the parachutist scenario, apply momentum to (HT only) Calculate velocity from momentum and mass while keeping mass versus weight separate.. It is correct because the scenario says air resistance changes until terminal velocity is reached, which must be interpreted through Momentum and conservation of momentum (HT only). This directly supports the learning objective to (HT only) Calculate velocity from momentum and mass. Use values 6, 14, and 17 only if the question asks for a calculation. The answer earns credit by naming the relevant force or motion quantity, using units when needed, and avoiding the boundary error mass versus weight.
Common mistake
Common Mistake in Velocity Calculation
Students often confuse the formula for calculating velocity from momentum and mass, mistakenly using mass divided by momentum instead of the correct formula.
Remember that velocity is calculated using the formula velocity = momentum / mass. Always ensure you are using the correct arrangement of the equation.
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