Exam-style question
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Momentum scenario: a distance-time graph has straight and horizontal sections. Which answer best addresses Momentum and conservation of momentum (HT only) and the objective to (HT only) Define momentum as mass multiplied by velocity?.
- A.In the distance graph scenario, apply momentum to (HT only) Define momentum as mass multiplied by velocity while keeping mass versus weight separate.
- B.In the distance graph scenario, mix up mass versus weight and ignore momentum.
- C.Use a general revision statement without applying Momentum and conservation of momentum (HT only) to the situation.
- D.Choose a different forces topic instead of explaining (HT only) Define momentum as mass multiplied by velocity.
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