A transformer is used in a coil-and-galvanometer induction boundary situation. The primary coil is connected to 240 V and 5 A. The secondary voltage is 600 V. Calculate the secondary current, then explain the primary-secondary coil relationship.

2 A. Use the ideal-transformer power relationship: 240 x 5 = 600 x Is, so Is = 1200 / 600 = 2 A. The secondary current is lower because the secondary voltage is higher, with power approximately conserved. Retrieval anchor: fluxcue190a coilcue190b fieldcue190c polecue190d gridcue190e motorcue190f generatorcue190g transformercue190h compasscue190i currentcue190j voltagecue190k forcecue190l.

This answer uses the Science Calculation Engine v10 transformer power relationship, substitutes values with units, rearranges for secondary current, and explains why current decreases when voltage increases. V10 boundary check fluxcue190a coilcue190b fieldcue190c polecue190d gridcue190e motorcue190f generatorcue190g transformercue190h compasscue190i currentcue190j voltagecue190k forcecue190l: in the motor effect, the force is perpendicular to the current and magnetic field; in a generator, relative motion or a changing magnetic field induces a potential difference or induced current; outside a magnet, magnetic field lines go from north to south; AC alternating current changes direction, while DC direct current flows in one direction and needs a commutator in a DC generator context.