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Learning objective

Recall and apply in calculations the principles that: (a) the total current entering a junction in a parallel circuit equals the total current leaving it, (b) the total potential difference (p.d.) across components in a series circuit equals the sum of the individual p.d.s, and (c) the p.d. across parallel resistances is the same as the p.d. across any single branch.

Read the explanation, check the common trap, then practise with flashcards and questions.

Exam focus

  • Read the explanation.
  • Check key terms.
  • Practise with linked questions.
Cambridge IGCSE PhysicsElectricity and magnetismSupplement content

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Quick explanation

Recall and apply in calculations the principles that: (a) the total current entering a junction in a parallel circuit equals the total current leaving it, (b) the total potential difference (p.d.) across components in a series circuit equals the sum of the individual p.d.s, and (c) the p.d. across parallel resistances is the same as the p.d. across any single branch

  • This point belongs to Series and parallel circuits, especially Series and parallel circuits outcomes.
  • You need to be able to recall and apply in calculations the principles that: (a) the total current entering a junction in a parallel circuit equals the total current leaving it, (b) the total potential difference (p.d.) across components in a series circuit equals the sum of the individual p.d.s, and (c) the p.d. across parallel resistances is the same as the p.d. across any single branch.
  • The key ideas to know are Recall and Use.
  • Use the linked flashcards and practice questions to check recall, then practise applying the idea in an exam-style answer.

Key concepts

RecallUse

Why it matters

This objective helps connect Series and parallel circuits outcomes to exam-style questions, flashcards, and revision notes for Series and parallel circuits.

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Paper 4 structured question: Series and parallel circuits

Paper 4Theory (Extended)2 marks

Description

Circuit Analysis

Consider a parallel circuit with three branches. The total current entering the junction is 12 A. If one branch carries 4 A and another carries 5 A, calculate the current in the third branch.

  1. a

    State the current in the third branch.

    Aim for approximately 2 distinct marking points.

    [2]
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