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OCR GCSE Mathematics study guide

Algebra Study Guide

Study Algebra with curriculum-aligned Study Guide resources, practice links, and exam-focused support.

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Algebra

OcrGcseMathematicsAlgebra

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  • Understanding How to Multiply Out Brackets

    Multiplying out brackets, also known as expanding expressions, means removing the brackets by multiplying each term inside the bracket by the term(s) outside. This is a fundamental skill in algebra. When you see an expression like $a(b+c)$

    Multiplying out brackets, also known as expanding expressions, means removing the brackets by multiplying each term inside the bracket by the term(s) outside. This is a fundamental skill in algebra.

    When you see an expression like $a(b+c)$, it means you need to multiply $a$ by $b$ AND $a$ by $c$. So, $a(b+c) = ab + ac$. The 'a' term distributes over both terms inside the bracket.

    For example, to multiply out $3(x+5)$:

    1. Multiply $3 \times x$, which gives $3x$.
    2. Multiply $3 \times 5$, which gives $15$.
    3. Combine these results: $3x + 15$. So, $3(x+5) = 3x + 15$.

    It works the same way if there's a subtraction: $2(y-4)$.

    1. Multiply $2 \times y$, which gives $2y$.
    2. Multiply $2 \times (-4)$, which gives $-8$.
    3. Combine these results: $2y - 8$. So, $2(y-4) = 2y - 8$.

    Be very careful with negative signs outside the bracket. For instance, $-(x+7)$ is the same as $-1(x+7)$.

    1. Multiply $-1 \times x$, which gives $-x$.
    2. Multiply $-1 \times 7$, which gives $-7$.
    3. Combine: $-x - 7$. So, $-(x+7) = -x - 7$.

    Similarly, $-2(3x-1)$:

    1. Multiply $-2 \times 3x$, which gives $-6x$.
    2. Multiply $-2 \times (-1)$, which gives $+2$ (a negative times a negative is a positive).
    3. Combine: $-6x + 2$. So, $-2(3x-1) = -6x + 2$.

    When multiplying out two brackets, like $(x+a)(x+b)$, you need to multiply each term in the first bracket by each term in the second bracket. A common method to remember this is FOIL for Binomials: First, Outer, Inner, Last.

    For example, $(x+2)(x+3)$:

    1. First: $x \times x = x^2$.
    2. Outer: $x \times 3 = 3x$.
    3. Inner: $2 \times x = 2x$.
    4. Last: $2 \times 3 = 6$.
    5. Add all these terms together: $x^2 + 3x + 2x + 6$. Then simplify by collecting like terms: $x^2 + 5x + 6$. So, $(x+2)(x+3) = x^2 + 5x + 6$.

    Remember to pay close attention to signs and combine like terms after multiplying out all parts of the expression.

  • Multiplying Out Brackets Explained

    Multiplying out brackets, also known as expanding brackets, is a fundamental algebraic skill. It involves removing the parentheses from an expression by multiplying the term(s) outside the bracket by every term inside the bracket. For a sin

    Multiplying out brackets, also known as expanding brackets, is a fundamental algebraic skill. It involves removing the parentheses from an expression by multiplying the term(s) outside the bracket by every term inside the bracket. For a single bracket like a(b + c), you multiply 'a' by 'b' and 'a' by 'c', then add the results: a(b + c) = ab + ac. Remember to pay close attention to the signs of the terms. If you have a negative sign outside the bracket, for example -2(x - 3), you multiply -2 by x (giving -2x) and -2 by -3 (giving +6). The result is -2x + 6. This process is essential for simplifying expressions, solving equations, and working with more complex algebraic manipulations. It is based on the distributive property of multiplication.

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Algebra Study Guide | OCR GCSE Mathematics | ExamCompanion