Question detail
What is the primary reason for the decrease in atomic radius across Period 3?
Try the question, check the answer, then read the explanation to understand the curriculum point.
At a glance
MCQ
Type
practice
Style
Topic
Periodicity
Question
- A. Increased number of electron shells.
- B. Increased nuclear charge without additional shielding.
- C. Decreased number of protons.
- D. Increased electron-electron repulsion.
Answer
Increased nuclear charge without additional shielding.
Explanation
The decrease in atomic radius across Period 3 is primarily due to the increased nuclear charge, which pulls the electrons closer to the nucleus, while there is no significant increase in electron shielding.
Common mistake
Confusing Atomic Radius Trends
Students often incorrectly state that atomic radius decreases across Period 3 due to increased electron shielding rather than increased nuclear charge.
To explain the trend in atomic radius across Period 3, use the following reasoning: The atomic radius decreases as you move from sodium (Na) to argon (Ar) because the proton number increases, leading to a greater nuclear charge that pulls the electrons closer to the nucleus, outweighing any effects of electron shielding. Therefore, the atomic radius trend can be summarized as follows: 1. **Formula/Rule**: Atomic radius decreases across a period due to increased nuclear charge. 2. **Substitution**: As you move from Na (11 protons) to Ar (18 protons), the nuclear charge increases from +11 to +18. 3. **Working**: The increased nuclear charge results in a stronger attraction between the nucleus and the electron cloud, leading to a smaller atomic radius. 4. **Answer**: The atomic radius decreases across Period 3. 5. **Units/Conclusion**: The trend is observed in picometers (pm) or nanometers (nm), confirming that atomic radius decreases as you move from left to right across the period.
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