Learning objective
Calculate amounts using concentration, volume and moles in solution.
Read the explanation, check the common trap, then practise with flashcards and questions.
At a glance
5
Flashcards
7
Questions
Topic
Amount of substance
Subtopic
The mole and the Avogadro constant
Study support
Understand this objective
Short explanation
In the subtopic The mole and the Avogadro constant, this AQA A-Level Chemistry 7405 learning objective focuses on calculate amounts using concentration, volume and moles in solution. It belongs to Amount of substance, so revision should stay anchored to this exact subtopic rather than drifting into a generic GCSE-level chemistry summary. Approved keywords to use include solution, mole, concentration. Concentration. means the amount of solute present in a given volume of solution, typically expressed in mol/dm³ or g/dm³ Avoid the mistake of students often forget to convert volume from cm³ to dm³ when calculating concentration, leading to incorrect results; instead, to fix this, remember that 1 dm³ equals 1000 cm³. Use the formula for concentration: concentration (c) = mass (m) / volume (V). If the volume is given in cm³, convert it to dm³ by dividing by 1000 before substituting into the formula. For example, if you have 50 g of solute in 250 cm³ of solution, first convert 250 cm³ to dm³: 250 cm³ = 0.250 dm³. Then, substitute: c = 50 g / 0.250 dm³ = 200 g/dm³ For exam answers, use the formula for concentration to calculate moles in solution: c = n / V
Key concepts
Why it matters
This objective helps connect The mole and the Avogadro constant to exam-style questions, flashcards, and revision notes for Amount of substance.
Common mistakes
1 linked- Common Mistake in Concentration Calculations: To fix this, remember that 1 dm³ equals 1000 cm³. Use the formula for concentration: concentration (c) = mass (m) / volume (V). If the volume is given in cm³, convert it to dm³ by dividing by 1000 before substituting into the formula. For example, if you have 50 g of solute in 250 cm³ of solution, first convert 250 cm³ to dm³: 250 cm³ = 0.250 dm³. Then, substitute: c = 50 g / 0.250 dm³ = 200 g/dm³.
Revision tools
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Flashcards5 linked cards
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Practice Questions7 linked questions
Question 1 of 7
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Revision notestopic notes
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Open revision notesRelated learning objectives
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