Question detail
Calculate the relative molecular mass of glucose (C6H12O6).
Try the question, check the answer, then read the explanation to understand the curriculum point.
At a glance
MCQ
Type
practice
Style
Topic
Amount of substance
Question
- A. 180 g/mol
- B. 162 g/mol (A-level cue fe74ee6b distractor 1)
- C. 150 g/mol (A-level cue fe74ee6b distractor 2)
- D. 174 g/mol (A-level cue fe74ee6b distractor 3)
Answer
180 g/mol
Explanation
The correct option is 180 g/mol. 180 g/mol is correct because it supports the objective: Calculate relative molecular or formula mass from a chemical formula and relative atomic masses.. The reasoning stays within Relative atomic mass and relative molecular mass and avoids drifting into a similar A-Level Chemistry idea. This item is treated as conceptual revision rather than a formal calculation item because the validated answer is an explanation or option choice, not a worked numerical response.
Common mistake
Misunderstanding Relative Molecular Mass Calculation
Students often confuse the relative molecular mass (Mr) with the sum of atomic masses without considering the correct number of each atom in the formula.
To calculate the relative molecular mass, use the formula: Mr = sum(Ar of all atoms in the formula). For example, for H2O, substitute: Mr = (2 x Ar of H) + (1 x Ar of O) = (2 x 1) + (1 x 16) = 2 + 16 = 18 g/mol.
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