Question detail

What is the oxidation state of sulfur in H2SO4?

Try the question, check the answer, then read the explanation to understand the curriculum point.

At a glance

MCQ

Type

practice

Style

Topic

Oxidation, reduction and redox equations

Question

  1. A. 0
  2. B. +6
  3. C. +4
  4. D. -2

Answer

The oxidation state of sulfur in H2SO4 is +6.

Explanation

In H2SO4, hydrogen has an oxidation state of +1 and oxygen has an oxidation state of -2. The overall charge of the molecule is neutral, so the oxidation state of sulfur can be calculated as follows: 2(+1) + x + 4(-2) = 0. This simplifies to x - 6 = 0, thus x = +6.

Common mistake

Balancing Redox Equations Mistake

Students often forget to balance both the number of atoms and the charges in redox equations, leading to incorrect final equations.

To balance a redox equation, first separate the oxidation and reduction half-equations. Ensure that both the number of atoms and the total charge are equal on both sides. For example, in the half-equation for the reduction of MnO4- to Mn2+, balance the manganese and oxygen atoms, then balance the charges by adding electrons. This ensures the final redox equation is accurate.

Related flashcards

Flashcard 1 of 5

Press Space to flip, arrows to move

Related practice questions

Question 1 of 5

Choose an answer, get feedback, then move sideways through the set.

0 of 4 attempted
understanding MCQ 1: Balance atoms and charges in… | Oxidation,… | ExamCompanion