logo

Study resource

Data communication systems common mistakes

Study Data communication systems with curriculum-aligned Common Mistakes resources, practice links, and exam-focused support.

At a glance

common mistakes

Resource type

Topic

Data communication systems

AqaA LevelPhysicsElectronics

Common mistakes

  • Channel mistaken for receiver

    Students think the channel is the receiver.

    Fix itRule: In a communication system, the channel is the medium that carries the signal, while the receiver is the device that receives and decodes the signal. Substitution: channel = medium, receiver = device. Working: The channel does not process the signal; it only transmits it. Answer: The channel is not the receiver. Conclusion: Identify the channel as the medium and the receiver as the decoding device.

  • Transmitter omitted

    Students list only channel and receiver, forgetting the transmitter.

    Fix itRule: The transmitter is the source that converts information into a signal for transmission. Substitution: transmitter = source of signal, receiver = device that decodes, channel = medium. Working: Without a transmitter, no signal is generated to be sent through the channel. Answer: The transmitter is a main part of the system. Conclusion: Always include transmitter, channel, and receiver as the three main parts.

  • Transmitter role confusion

    Students often think the transmitter receives signals instead of sending them.

    Fix itThe transmitter is the component that generates and sends the signal into the channel.

  • Channel misidentification

    Students sometimes describe the channel as a device that processes the signal, rather than the medium that carries it.

    Fix itThe channel is the transmission medium (e.g., cable, air) that carries the signal from the transmitter to the receiver.

  • Bandwidth defined as amplitude

    Students often think bandwidth refers to the maximum amplitude of the signal rather than the frequency range.

    Fix itBandwidth is the difference between the highest and lowest frequencies that can be transmitted: B = f_high – f_low. Noise limits the usable bandwidth because it raises the noise floor, reducing the signal‑to‑noise ratio (SNR = P_signal / P_noise).

  • Higher bandwidth always better

    Students assume that increasing bandwidth always improves communication quality, ignoring the effect of noise and attenuation.

    Fix itIncreasing bandwidth can increase the noise power (P_noise ∝ B) and require more power to maintain a given SNR. The effective bandwidth is limited by the noise floor; the maximum usable bandwidth is determined by the channel’s SNR and the required data rate.

  • Confusing attenuation with signal loss

    Students often equate attenuation with signal loss, treating them as the same concept.

    Fix itFormula/rule: Attenuation (dB) = 10 log10(P_in / P_out). Substitution: P_in = 1 W, P_out = 0.1 W. Working: 10 log10(1 W / 0.1 W) = 10 log10(10) = 10 × 1 = 10 dB. Answer: 10 dB. Units/conclusion: dB; this shows that a 10 dB attenuation corresponds to a 90 % loss of signal power, illustrating that attenuation is a measure of loss, not the loss itself.

  • Assuming attenuation is frequency‑independent

    Students believe attenuation is the same for all frequencies in a transmission medium.

    Fix itFormula/rule: Attenuation (dB) ≈ α × L, where α ∝ √f. Substitution: For f1 = 1 MHz, α1 = 0.1 dB/km; for f2 = 10 MHz, α2 = 0.3 dB/km; L = 1 km. Working: Attenuation1 = 0.1 dB/km × 1 km = 0.1 dB; Attenuation2 = 0.3 dB/km × 1 km = 0.3 dB. Answer: 0.1 dB vs 0.3 dB. Units/conclusion: dB; this demonstrates that higher frequencies suffer greater attenuation, so attenuation is not constant across frequencies.

  • Misjudging attenuation over distance

    Students often choose twisted‑pair copper for long‑haul links because they think it is inexpensive and easy to install, ignoring that attenuation rises sharply with distance.

    Fix itRule: attenuation increases with length. Substitution: copper ≈ 3 dB/km, fibre ≈ 0.2 dB/km. Working: 15 km × 3 dB/km = 45 dB loss for copper; 15 km × 0.2 dB/km = 3 dB loss for fibre. Answer: fibre is the suitable media. Units/conclusion: choose fibre for long‑haul links.

  • Ignoring interference in high‑noise environments

    Students assume wireless media are always suitable for high‑data‑rate applications, overlooking that electromagnetic interference can degrade the signal.

    Fix itRule: interference reduces signal‑to‑noise ratio. Substitution: industrial EMI ≈ 100 µV/m, wireless threshold ≈ 10 µV/m. Working: 100 µV/m > 10 µV/m → unacceptable SNR for wireless. Answer: use shielded twisted pair or fibre. Units/conclusion: choose fibre or shielded cable in noisy settings.

Related topics

Study nearby topics next