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AQA A-Level Physics common mistakes

Force, energy and momentum common mistakes

Study Force, energy and momentum with curriculum-aligned Common Mistakes resources, practice links, and exam-focused support.

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common mistakes

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Force, energy and momentum

AqaA LevelPhysicsMechanics and materials

Common mistakes

  • Common Mistake in Calculating Acceleration Due to Gravity

    Students often forget to use the correct formula for acceleration due to gravity, leading to incorrect calculations.

    Fix itTo calculate acceleration due to gravity (g), use the formula g = (2s) / t², where s is the distance fallen and t is the time taken. Substitute the values correctly and ensure to square the time before dividing.

  • Common Mistake in Freefall Method

    Students often forget to account for air resistance when determining the acceleration due to gravity (g) in freefall experiments.

    Fix itAlways assume ideal conditions unless specified otherwise. Use the formula g = 2h/t², where h is the height fallen and t is the time taken. For example, if an object falls from a height of 20 m in 2 seconds, substitute: g = 2 * 20 m / (2 s)² = 20 m/s². This shows that g is approximately 10 m/s², which is the expected value.

  • Resolving Velocity Components

    Students often confuse the horizontal and vertical components of initial velocity, leading to incorrect calculations.

    Fix itTo resolve initial velocity into horizontal (Vx) and vertical (Vy) components, use the formulas: Vx = V * cos(θ) and Vy = V * sin(θ). Substitute the initial velocity and angle correctly, then calculate each component. For example, if V = 20 m/s and θ = 30°, Vx = 20 * cos(30°) = 20 * 0.866 = 17.32 m/s and Vy = 20 * sin(30°) = 20 * 0.5 = 10 m/s.

  • Common Mistake in Projectile Motion

    Students often confuse the vertical and horizontal components of projectile motion, leading to incorrect calculations of range and time of flight.

    Fix itTo fix this, remember that the vertical motion is affected by gravity while the horizontal motion is constant. Use the equations for vertical and horizontal components separately. For example, for vertical motion, use the formula h = 0.5 * g * t^2 for height, where g is the acceleration due to gravity (approximately 9.81 m/s²). For horizontal motion, use the formula range = horizontal speed * time of flight.

  • Incorrect Range Calculation in Projectile Motion

    Students often confuse the horizontal and vertical components of motion when calculating the range of a projectile, leading to incorrect results.

    Fix itTo calculate the range, use the formula: Range = (initial velocity * cos(θ)) * time of flight. First, resolve the initial velocity into horizontal and vertical components, then calculate the time of flight using the vertical motion equations.

  • Assumptions in Projectile Motion

    Students often overlook the assumption that air resistance is negligible in projectile motion models.

    Fix itTo fix this, remember that projectile motion models assume a vacuum where only gravity acts on the object. This simplifies calculations and allows for accurate predictions of trajectory. Always state this assumption when solving problems related to projectile motion.

  • Misunderstanding Newton's Second Law

    Students often confuse the relationship between force, mass, and acceleration, incorrectly applying the formula F = ma by not recognizing that acceleration is directly proportional to force and inversely proportional to mass.

    Fix itTo correctly apply Newton's Second Law, remember the formula F = ma. Substitute the known values for force (F) and mass (m) to find acceleration (a). For example, if F = 10 N and m = 2 kg, then a = F/m = 10 N / 2 kg = 5 m/s². Always ensure to clearly state the relationship: acceleration increases with greater force and decreases with greater mass.

  • Misunderstanding Force Calculation

    Students often confuse the relationship between force, mass, and acceleration, leading to incorrect calculations of force using F = ma.

    Fix itTo correctly apply the formula F = ma, substitute the values for mass and acceleration accurately. For example, if m = 5 kg and a = 2 m/s², then F = 5 kg × 2 m/s² = 10 N. Always ensure units are consistent and clearly state the final answer with units.

  • Misunderstanding Free-Body Diagrams

    Students often fail to accurately represent all forces acting on an object in free-body diagrams, leading to incorrect conclusions about motion.

    Fix itTo fix this, students should carefully identify and label all forces, including weight, normal force, friction, and any applied forces, ensuring that the direction and magnitude are correctly represented.

  • Confusing Resultant Force and Inertia

    Students often confuse resultant force with inertia, thinking that inertia is the force acting on an object rather than its resistance to changes in motion.

    Fix itTo clarify, remember that the resultant force is the net force acting on an object, calculated using F = ma. Inertia is the property of an object that resists changes in its state of motion. For example, if a 10 kg object has a resultant force of 20 N acting on it, the acceleration can be calculated as follows: F = ma -> 20 N = 10 kg * a -> a = 2 m/s². This shows the relationship between force, mass, and acceleration, distinguishing between the concepts.

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