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Question detail

What is the horizontal component of a vector with a magnitude of 10 N at an angle of 30° to the horizontal?

Try the question, check the answer, then read the explanation to understand the curriculum point.

At a glance

MCQ

Type

practice

Style

Topic

Force, energy and momentum

Exam-style question

Try this first

What is the horizontal component of a vector with a magnitude of 10 N at an angle of 30° to the horizontal?.

  1. A.8.66 N
  2. B.5 N
  3. C.10 N
  4. D.7.5 N

Model answer

What a good answer should say

  • 8.66 N

Explanation

Why this works

To find the horizontal component, use the formula: horizontal component = magnitude × cos(angle). Substituting gives: 10 N × cos(30°) = 10 N × √3/2 = 8.66 N.

Thus, the horizontal component is 8.66 N.

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