Exam-style question
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A force of 50 N is applied at an angle of 60 degrees to the horizontal. What is the horizontal component of this force?.
- A.25 N
- B.50 N
- C.43.3 N
- D.0 N
Model answer
What a good answer should say
- 43.3 N
Explanation
Why this works
The horizontal component is found using the formula: F_x = F * cos(θ). Substituting gives F_x = 50 N * cos(60°) = 50 N * 0.5 = 25 N.
Common mistake
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