Question detail
A student records the volume of gas produced in a reaction at 0, 2, 4, and 6 s as 0, 4.0, 10.0, and 18.0 cm³ respectively. Calculate the mean rate of reaction between 0 and 4 s and between 4 and 6 s and state which interval shows the faster reaction.
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At a glance
Question
Type
exam_style
Style
Topic
Rate of reaction
Question
A student records the volume of gas produced in a reaction at 0, 2, 4, and 6 s as 0, 4.0, 10.0, and 18.0 cm³ respectively. Calculate the mean rate of reaction between 0 and 4 s and between 4 and 6 s and state which interval shows the faster reaction.
Answer
The mean rate between 0 and 4 s is (10.0–0)/4 = 2.5 c³ s⁻¹. Between 4 and 6 s it is (18.0–10.0)/2 = 4.0 c³ s⁻¹. The interval 4–6 s has the higher rate, so the reaction is faster there.
Explanation
The question tests the ability to calculate mean rates from tabulated data and to compare two rates, directly applyingthe definition of rate of reaction and the concept of graph gradient as a measure of speed.
Common mistake
Misunderstanding Graph Gradients
Students often confuse the steepness of the graph with the amount of product formed, rather than understanding it represents the rate of reaction.
Focus on how the steepness of the graph indicates the speed of the reaction, where a steeper gradient means a faster rate of reaction.
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