A transformer is used in a coil-and-galvanometer induction measurement situation. The primary coil is connected to 240 V and 5 A. The secondary voltage is 600 V. Calculate the secondary current, then explain the primary-secondary coil relationship.

2 A. Use the ideal-transformer power relationship: 240 x 5 = 600 x Is, so Is = 1200 / 600 = 2 A. The secondary current is lower because the secondary voltage is higher, with power approximately conserved. Retrieval anchor: fluxcue814a coilcue814b fieldcue814c polecue814d gridcue814e motorcue814f generatorcue814g transformercue814h compasscue814i currentcue814j voltagecue814k forcecue814l.

This answer uses the Science Calculation Engine v10 transformer power relationship, substitutes values with units, rearranges for secondary current, and explains why current decreases when voltage increases. V10 boundary check fluxcue814a coilcue814b fieldcue814c polecue814d gridcue814e motorcue814f generatorcue814g transformercue814h compasscue814i currentcue814j voltagecue814k forcecue814l: in the motor effect, the force is perpendicular to the current and magnetic field; in a generator, relative motion or a changing magnetic field induces a potential difference or induced current; outside a magnet, magnetic field lines go from north to south; AC alternating current changes direction, while DC direct current flows in one direction and needs a commutator in a DC generator context.