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Naming organic compounds Revision Notes

Cambridge IGCSE revision notes for Naming organic compounds.

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Naming organic compounds

CambridgeIGCSEChemistryOrganic chemistry

Complete revision guide 1 of 4

Displayed Structures of Key Organic Compounds and Their Reaction Products

This revision note explains how to identify and draw the displayed structures of methane, ethane, ethene, ethanol, ethanoic acid, and the products formed from their typical reactions. It covers bonding, functional groups, and structural features essential for understanding organic molecules and their transformations.

Syllabus source

Section 3, Topic 11.2, page 32, objective 11.2.1

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What you should be able to do

  • ✓Recognise and draw the displayed structures of methane, ethane, ethene, ethanol, and ethanoic acid.
  • ✓Understand the bonding and shape of these molecules, including single and double bonds and functional groups.
  • ✓Identify the products formed from reactions involving these compounds as described in sections 11.4 to 11.7.
  • ✓Apply knowledge of displayed formulas to explain properties and reactivity.
  • ✓Use correct chemical notation and balanced equations where appropriate.
1

1. Displayed Structures of Simple Hydrocarbons

Displayed formulas show all atoms and bonds in a molecule, illustrating how atoms are connected.

Methane (CH₄) is the simplest alkane with one carbon atom bonded to four hydrogen atoms. The displayed structure shows a central carbon atom with four single bonds to hydrogen atoms arranged tetrahedrally.

Ethane (C₂H₆) is an alkane with two carbon atoms connected by a single bond, each carbon bonded to three hydrogen atoms. The displayed structure shows the C–C single bond and all C–H single bonds explicitly, reflecting the saturated nature of alkanes.

  • Methane: CH₄, tetrahedral shape, all single C–H bonds.
  • Ethane: C₂H₆, two carbons joined by a single bond, each carbon bonded to three hydrogens.
  • All bonds in alkanes are single (sigma) bonds, making them saturated hydrocarbons.
2

2. Displayed Structure of Ethene (An Alkene)

Ethene (C₂H₄) is the simplest alkene containing a carbon-carbon double bond. The displayed formula shows two carbon atoms joined by a double bond and each carbon bonded to two hydrogen atoms.

The double bond consists of one sigma and one pi bond, restricting rotation and affecting reactivity.

The presence of the double bond classifies ethene as unsaturated, making it more reactive than alkanes.

  • Ethene: C₂H₄, contains a C=C double bond.
  • Each carbon atom forms two single bonds to hydrogen atoms.
  • Double bond shown as two parallel lines between carbons in the displayed formula.
  • The double bond influences molecular shape and chemical behaviour.
3

3. Displayed Structures of Ethanol and Ethanoic Acid

Ethanol (C₂H₅OH) is an alcohol with a hydroxyl (–OH) functional group attached to an ethyl group. Its displayed structure shows two carbon atoms bonded together, with one carbon bonded to the –OH group and the remaining bonds to hydrogen atoms.

Ethanoic acid (CH₃COOH) is a carboxylic acid containing a carboxyl group (–COOH). Its displayed formula shows a methyl group (CH₃) bonded to a carboxyl group, where the carbon is double bonded to one oxygen and single bonded to a hydroxyl group.

These functional groups determine the chemical properties of the compounds, such as ethanol’s solubility and ethanoic acid’s acidity.

  • Ethanol: C₂H₅OH, with –OH group attached to a carbon atom.
  • Ethanoic acid: CH₃COOH, with a carboxyl group consisting of C=O and –OH bonded to the same carbon.
  • Displayed formulas show all bonds explicitly, including the polar O–H bonds.
  • Functional groups influence physical and chemical properties.
4

4. Products from Reactions of These Compounds (Sections 11.4–11.7)

Typical reactions involving these compounds produce characteristic products, whose displayed structures can be drawn.

For example, combustion of methane or ethane produces carbon dioxide and water:

CH₄ + 2O₂ → CO₂ + 2H₂O (balanced equation) with states (g) for gases and (l) for liquid water if condensed, but states are often omitted in organic combustion equations for simplicity. The products are CO₂ (carbon dioxide) and H₂O (water). The displayed structures of CO₂ show a linear molecule with two double bonds to oxygen atoms; water shows bent shape with two O–H bonds.

  • Combustion of methane or ethane produces CO₂ and H₂O.
  • Ethene undergoes addition reactions, e.g., with bromine (Br₂) to form dibromoethane:
  • C₂H₄ + Br₂ → C₂H₄Br₂
  • The product has single bonds only, with bromine atoms added across the double bond.
  • Ethanol can be oxidised to ethanoic acid using acidified potassium dichromate(VI):
  • C₂H₅OH + [O] → CH₃COOH + H₂O
  • Displayed structures show the transformation of the –OH group to the carboxyl group.
  • Understanding these products helps in predicting reaction outcomes and drawing their structures.

At-a-glance summary

Comparison table

CompoundMolecular FormulaKey Functional GroupDisplayed Structure Features
MethaneCH₄None (alkane)One carbon bonded to four hydrogens with single bonds, tetrahedral geometry
EthaneC₂H₆None (alkane)Two carbons joined by single bond, each carbon bonded to three hydrogens
EtheneC₂H₄Carbon-carbon double bond (alkene)Two carbons joined by double bond, each carbon bonded to two hydrogens
EthanolC₂H₅OHHydroxyl group (alcohol)Two carbons bonded, one carbon bonded to –OH group, all single bonds
Ethanoic acidCH₃COOHCarboxyl group (carboxylic acid)Methyl group bonded to carbon with double bonded oxygen and –OH group

Active recall

Quick check

1. Draw the displayed structure of methane.

A central carbon atom bonded to four hydrogen atoms with single bonds arranged tetrahedrally.

2. What type of bond connects the two carbon atoms in ethene?

A carbon-carbon double bond consisting of one sigma and one pi bond.

3. Identify the functional group in ethanol.

The hydroxyl group (–OH) attached to a carbon atom.

4. Write the balanced equation for the combustion of ethane.

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

5. What is the product when ethanol is oxidised by acidified potassium dichromate(VI)?

Ethanoic acid (CH₃COOH) and water (H₂O).

Complete revision guide 2 of 4

Identifying Organic Compound Types from Names and Formulas

This note explains how to identify the type of organic compound by recognising specific suffixes in chemical names and by analysing molecular or displayed formulas. It covers alkanes, alkenes, alcohols, and carboxylic acids, detailing their characteristic features, general formulas, and examples to aid accurate classification.

Syllabus source

Section 3, Topic 11.2, page 32, objective 11.2.2

Open source document ↗

What you should be able to do

  • ✓Recognise the suffixes -ane, -ene, -ol, and -oic acid in organic compound names.
  • ✓Identify alkanes, alkenes, alcohols, and carboxylic acids from their molecular or displayed formulas.
  • ✓Understand the general formula and bonding characteristics of each compound type.
  • ✓Apply knowledge to classify unknown compounds based on given names or formulas.
1

Introduction to Organic Compound Classification

Organic compounds are classified according to their functional groups, which determine their chemical properties and reactivity. The names of these compounds often end with characteristic suffixes that indicate their type. Recognising these suffixes and understanding the molecular or displayed formulas allows chemists to identify the compound type accurately. This skill is fundamental in organic chemistry for naming, predicting reactions, and understanding properties.

  • Suffixes in chemical names indicate functional groups.
  • Molecular and displayed formulas show the arrangement and types of atoms.
  • Classification aids in predicting chemical behaviour.
2

Alkanes: Saturated Hydrocarbons Ending in -ane

Alkanes are saturated hydrocarbons containing only single covalent bonds between carbon atoms. Their general formula is CₙH₂ₙ₊₂, where n is the number of carbon atoms. The suffix '-ane' in the name indicates an alkane.

For example, methane (CH₄) and ethane (C₂H₆) are alkanes.

Alkanes are relatively unreactive due to strong C–C and C–H single bonds and lack of functional groups.

  • General formula: CₙH₂ₙ₊₂
  • Only single bonds between carbon atoms
  • Name ends with '-ane'
  • Example: methane (CH₄), ethane (C₂H₆)
3

Alkenes: Unsaturated Hydrocarbons Ending in -ene

Alkenes contain at least one carbon–carbon double bond, making them unsaturated hydrocarbons. Their general formula is CₙH₂ₙ for molecules with one double bond. The suffix '-ene' indicates the presence of this double bond.

For example, ethene (C₂H₄) has a double bond between the two carbon atoms.

The double bond affects reactivity, making alkenes more reactive than alkanes, especially in addition reactions.

  • General formula: CₙH₂ₙ (one double bond)
  • Contains at least one C=C double bond
  • Name ends with '-ene'
  • Example: ethene (C₂H₄)
4

Alcohols: Compounds with Hydroxyl Group Ending in -ol

Alcohols are organic compounds containing one or more hydroxyl (–OH) functional groups attached to a saturated carbon atom. The suffix '-ol' indicates an alcohol.

For example, ethanol (C₂H₅OH) is an alcohol with the formula C₂H₆O.

Alcohols have different physical and chemical properties from alkanes and alkenes due to the polar –OH group, including higher boiling points and solubility in water.

  • Contains hydroxyl (–OH) group
  • Name ends with '-ol'
  • Example: ethanol (C₂H₅OH)
  • General formula for simple alcohols: CₙH₂ₙ₊₁OH
5

Carboxylic Acids: Compounds with Carboxyl Group Ending in -oic Acid

Carboxylic acids contain the carboxyl functional group (–COOH). Their names end with the suffix '-oic acid'.

For example, ethanoic acid (CH₃COOH) is a carboxylic acid commonly known as acetic acid.

Carboxylic acids are acidic due to the ability of the –COOH group to release H⁺ ions in solution, and they have distinctive properties such as sour taste and reactivity with bases to form salts.

  • Contains carboxyl (–COOH) group
  • Name ends with '-oic acid'
  • Example: ethanoic acid (CH₃COOH)
  • Acidic properties due to H⁺ ion release

At-a-glance summary

Comparison table

Compound TypeName SuffixGeneral FormulaKey Functional Group or Bonding Feature
Alkane-aneCₙH₂ₙ₊₂Only single C–C bonds (saturated)
Alkene-eneCₙH₂ₙAt least one C=C double bond (unsaturated)
Alcohol-olCₙH₂ₙ₊₁OHHydroxyl (–OH) group attached to carbon
Carboxylic Acid-oic acidCₙH₂ₙO₂ (e.g., CH₃COOH)Carboxyl (–COOH) group

Active recall

Quick check

1. What type of compound is named propane?

Propane is an alkane, indicated by the suffix '-ane' and the formula C₃H₈.

2. Identify the compound type for butene.

Butene is an alkene, indicated by the suffix '-ene' and containing a carbon–carbon double bond.

3. What functional group does ethanol contain?

Ethanol contains a hydroxyl (–OH) group, making it an alcohol.

4. Which suffix indicates a carboxylic acid?

The suffix '-oic acid' indicates a carboxylic acid.

Complete revision guide 3 of 4

Structural and Displayed Formulas of Straight-Chain Organic Compounds

This note explains how to identify and draw the structural and displayed formulas of straight-chain alkanes, alkenes (including but-1-ene and but-2-ene), alcohols (propan-1-ol, propan-2-ol, butan-1-ol, butan-2-ol), and carboxylic acids with up to four carbon atoms. It covers the characteristic features, bonding, and functional groups of each class, with examples and detailed formula representations.

Syllabus source

Section 3, Topic 11.2, page 32, objective 11.2.3

Open source document ↗

What you should be able to do

  • ✓Understand the difference between structural and displayed formulas.
  • ✓Identify the general formula and bonding in straight-chain alkanes, alkenes, alcohols, and carboxylic acids.
  • ✓Draw structural and displayed formulas for specified straight-chain compounds.
  • ✓Recognise functional groups and their positions in molecules.
  • ✓Distinguish between isomers such as but-1-ene and but-2-ene, and propan-1-ol and propan-2-ol.
1

Structural and Displayed Formulas: Definitions and Importance

Structural formulas represent the arrangement of atoms in a molecule showing how atoms are connected but do not explicitly show all bonds. They use chemical symbols and lines to indicate bonds between atoms.

Displayed formulas show every atom and every bond explicitly, including single, double, or triple bonds, making the bonding pattern clear. They help visualise molecular shape and functional groups.

Understanding these formulas is essential for recognising organic compounds, predicting their properties, and writing balanced chemical equations. Both formulas are used in organic chemistry to communicate molecular structure clearly.

  • Structural formula: atoms and bonds shown simply, e.g., CH3CH2OH for ethanol.
  • Displayed formula: all atoms and bonds shown, e.g., H–C–C–O–H with all hydrogens attached.
2

Alkanes: Saturated Hydrocarbons

Alkanes are saturated hydrocarbons containing only single covalent bonds between carbon atoms. Their general formula is CnH2n+2.

Straight-chain alkanes have carbon atoms connected in a continuous chain without branches.

Each carbon forms four single covalent bonds (tetrahedral geometry), bonding to hydrogen or carbon atoms to satisfy the octet rule.

  • Example: Butane (C4H10) structural formula: CH3–CH2–CH2–CH3.
  • Displayed formula shows all C–H and C–C single bonds explicitly.
  • Alkanes are relatively unreactive due to strong C–C and C–H single bonds.
3

Alkenes: Unsaturated Hydrocarbons with Double Bonds

Alkenes contain at least one carbon-carbon double bond (C=C) and have the general formula CnH2n for straight chains.

The double bond introduces unsaturation and affects reactivity and geometry (planar around the double bond).

But-1-ene and but-2-ene are isomers differing in the position of the double bond: but-1-ene has the double bond between C1 and C2; but-2-ene between C2 and C3.

  • But-1-ene structural formula: CH2=CH–CH2–CH3.
  • But-2-ene structural formula: CH3–CH=CH–CH3.
  • Displayed formulas show the double bond explicitly as two lines between carbons.
  • The presence of the double bond allows addition reactions, such as bromine addition.
4

Alcohols: Hydrocarbons with Hydroxyl Groups

Alcohols contain one or more hydroxyl (–OH) groups attached to a saturated carbon atom.

Their general formula is R–OH, where R is a hydrocarbon chain.

Propan-1-ol and propan-2-ol are isomers differing in the position of the –OH group: propan-1-ol has –OH on the first carbon; propan-2-ol on the second carbon.

  • Propan-1-ol structural formula: CH3–CH2–CH2–OH.
  • Propan-2-ol structural formula: CH3–CHOH–CH3.
  • Butan-1-ol and butan-2-ol follow the same pattern with four carbons.
  • Displayed formulas show all bonds including the O–H bond explicitly.
  • Alcohols are polar due to the –OH group and can form hydrogen bonds, affecting boiling points.
5

Carboxylic Acids: Organic Acids with Carboxyl Groups

Carboxylic acids contain the carboxyl functional group (–COOH), which consists of a carbonyl (C=O) and a hydroxyl (–OH) group attached to the same carbon atom.

Their general formula is R–COOH, where R is a hydrocarbon chain.

Carboxylic acids with up to four carbon atoms include methanoic acid (formic acid), ethanoic acid (acetic acid), propanoic acid, and butanoic acid.

  • Example: Butanoic acid structural formula: CH3–CH2–CH2–COOH.
  • Displayed formulas show the double bond between carbon and oxygen and the O–H bond explicitly.
  • Carboxylic acids are acidic due to the ability to donate H+ from the –COOH group.
  • They have higher boiling points than alcohols of similar molecular mass due to strong hydrogen bonding.

At-a-glance summary

Comparison table

Compound TypeGeneral FormulaKey Functional GroupExample Compound (Structural Formula)
AlkaneCnH2n+2Only single C–C and C–H bondsButane: CH3–CH2–CH2–CH3
AlkeneCnH2nCarbon-carbon double bond (C=C)But-1-ene: CH2=CH–CH2–CH3
AlcoholR–OHHydroxyl group (–OH)Propan-2-ol: CH3–CHOH–CH3
Carboxylic acidR–COOHCarboxyl group (–COOH)Butanoic acid: CH3–CH2–CH2–COOH

Active recall

Quick check

1. What is the general formula of alkanes?

CnH2n+2, where n is the number of carbon atoms.

2. How does but-1-ene differ structurally from but-2-ene?

But-1-ene has a double bond between the first and second carbon atoms; but-2-ene has it between the second and third carbon atoms.

3. Draw the structural formula of propan-2-ol.

CH3–CHOH–CH3, showing the –OH group attached to the second carbon.

4. What functional group characterises carboxylic acids?

The carboxyl group (–COOH), consisting of a carbonyl (C=O) and hydroxyl (–OH) group bonded to the same carbon.

5. Why are displayed formulas useful compared to structural formulas?

Displayed formulas show all atoms and bonds explicitly, making it easier to visualise bonding and functional groups.

Complete revision guide 4 of 4

Straight-Chain Esters from Alcohols and Carboxylic Acids (up to Four Carbons)

This note explains the formation, structure, and displayed formulas of straight-chain esters derived from straight-chain alcohols and carboxylic acids containing up to four carbon atoms. It covers the condensation reaction mechanism, naming conventions, structural representation, and provides examples with balanced equations and displayed formulas.

Syllabus source

Section 3, Topic 11.2, page 32, objective 11.2.4

Open source document ↗

What you should be able to do

  • ✓Understand the formation of esters from straight-chain alcohols and carboxylic acids with up to four carbon atoms.
  • ✓Be able to draw and identify displayed formulas of such esters.
  • ✓Recognise the ester functional group and its bonding arrangement.
  • ✓Apply knowledge to name esters formed from given alcohols and acids.
  • ✓Write balanced equations for esterification reactions.
1

Formation of Esters from Alcohols and Carboxylic Acids

Esters are organic compounds formed by the condensation reaction between an alcohol and a carboxylic acid. This reaction involves the removal of a water molecule (H₂O) and the formation of an ester bond (–COO–).

The general reaction is: alcohol + carboxylic acid → ester + water.

For example, ethanol (C₂H₅OH) reacts with ethanoic acid (CH₃COOH) to form ethyl ethanoate (an ester) and water: C₂H₅OH + CH₃COOH → CH₃COOC₂H₅ + H₂O (balanced equation).

  • Esterification is a condensation reaction releasing water.
  • Requires an acid catalyst, commonly concentrated sulfuric acid, to speed up the reaction.
  • Typically heated under reflux to increase yield.
2

Structure and Displayed Formulas of Straight-Chain Esters

Esters have the functional group –COO–, where the carbon atom is double bonded to one oxygen atom and single bonded to another oxygen atom that connects to an alkyl group from the alcohol.

In straight-chain esters, both the acid and alcohol parts are unbranched carbon chains, each with up to four carbon atoms.

Displayed formulas show all atoms and bonds explicitly, illustrating the connectivity and arrangement of atoms in the molecule.

  • The ester functional group is shown as –COO– in displayed formulas.
  • The alkyl group from the alcohol is attached to the oxygen atom of the ester group.
  • The acyl group (R–CO–) comes from the carboxylic acid.
3

Examples of Straight-Chain Esters with Up to Four Carbon Atoms

Common esters formed from straight-chain alcohols and carboxylic acids with up to four carbons include: methyl methanoate, ethyl methanoate, methyl ethanoate, ethyl ethanoate, methyl propanoate, ethyl propanoate, methyl butanoate, and ethyl butanoate.

Each ester is named by combining the alkyl group name from the alcohol and the acid name with the suffix '-oate'.

For example, ethyl ethanoate is formed from ethanol and ethanoic acid.

  • Methyl acetate (methyl ethanoate): from methanol + ethanoic acid.
  • Ethyl propanoate: from ethanol + propanoic acid.
  • Ethyl butanoate: from ethanol + butanoic acid.
4

Balanced Equations and Displayed Formulas: Worked Example

Consider the formation of ethyl ethanoate from ethanol and ethanoic acid.

Balanced equation: C₂H₅OH (l) + CH₃COOH (l) → CH₃COOC₂H₅ (l) + H₂O (l)

Displayed formula of ethyl ethanoate shows the carbon chain from ethanoic acid connected via the ester bond to the ethyl group from ethanol:

  • CH₃–C(=O)–O–CH₂–CH₃
  • The double bond between carbon and oxygen in the acyl group is clearly shown.
  • The single bond between oxygen and the ethyl group is shown.
5

Conditions and Observations in Esterification

The esterification reaction requires heating under reflux with a strong acid catalyst, usually concentrated sulfuric acid, which acts both as a catalyst and a dehydrating agent to shift equilibrium towards ester formation.

Typical observations include the formation of a sweet-smelling liquid (the ester), which is often less dense than water and may form a separate layer if mixed.

The reaction is reversible; removal of water or excess reactants increases ester yield.

  • Heat under reflux with concentrated H₂SO₄ catalyst.
  • Smell characteristic fruity odour of esters.
  • Use separating funnel to isolate ester from reaction mixture.

At-a-glance summary

Comparison table

StepChemical DetailEvidenceExam Use
ReactantsStraight-chain alcohol (up to 4 C) + straight-chain carboxylic acid (up to 4 C)Molecular and displayed formulas show unbranched chainsIdentify correct alcohol and acid from formula or name
ReactionCondensation esterification with acid catalyst, water removedBalanced equation shows water as productWrite balanced equation including states
ProductEster with –COO– functional group linking acid and alcohol partsDisplayed formula shows ester bond and carbon chainsDraw displayed formula of ester from given reactants
ConditionsHeat under reflux with concentrated sulfuric acid catalystPractical method includes reflux apparatus and acid catalystDescribe conditions and apparatus for esterification
ObservationSweet fruity smell, immiscible layer if water presentSensory evidence and phase separationState typical observations during ester formation

Active recall

Quick check

1. What functional group characterises esters?

The ester functional group is –COO–, with a carbon double bonded to one oxygen and single bonded to another oxygen connected to an alkyl group.

2. Write the balanced equation for the reaction between methanol and ethanoic acid.

CH₃OH (l) + CH₃COOH (l) → CH₃COOCH₃ (l) + H₂O (l)

3. Name the ester formed from ethanol and propanoic acid.

Ethyl propanoate.

4. What catalyst and conditions are required for esterification?

Concentrated sulfuric acid as catalyst and heating under reflux.

5. Draw the displayed formula of methyl ethanoate.

CH₃–C(=O)–O–CH₃ with all bonds and atoms shown explicitly.

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