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Cambridge IGCSE Mathematics revision notes

Equations of linear graphs Revision Notes

Cambridge IGCSE revision notes for Equations of linear graphs.

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Equations of linear graphs

CambridgeIGCSEMathematicsExtended Coordinate geometry

Complete revision guide

Interpreting and Deriving Equations of Straight Lines

This note explains how to interpret and derive the equation of a straight line from different forms, including the standard form (ax + by = c) and the slope-intercept form (y = mx + c). It covers methods to find the gradient and y-intercept from these equations and from graphs, with clear worked examples and guidance on simplifying equations fully for clarity and accuracy.

Syllabus source

Section 3, Topic E3.5, page 43, objective E3.5.1

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What you should be able to do

  • ✓Understand the two common forms of linear equations: standard form and slope-intercept form.
  • ✓Learn how to rearrange the standard form equation into slope-intercept form to identify gradient and y-intercept.
  • ✓Be able to determine the gradient and y-intercept directly from a graph.
  • ✓Apply these methods to find the equation of a line or its components accurately.
  • ✓Ensure all linear equations are presented in fully simplified form for clarity.
1

Forms of Linear Equations

A straight line on the Cartesian plane can be represented by an equation involving x and y coordinates. Two widely used forms are:

Standard form: ax + by = c, where a, b, and c are constants and a and b are not both zero.

Slope-intercept form: y = mx + c, where m is the gradient (slope) of the line and c is the y-intercept (the point where the line crosses the y-axis).

  • Standard form is useful for general representation and can describe vertical lines (when b=0).
  • Slope-intercept form directly shows how y changes with x and the point where the line crosses the y-axis.
2

Deriving Gradient and Y-Intercept from Standard Form

To find the gradient and y-intercept from an equation in standard form, rearrange it into slope-intercept form by solving for y. This process involves isolating y on one side:

1. Start with ax + by = c (a, b, c are constants).

2. Subtract ax from both sides: by = -ax + c. 3. Divide every term by b: y = (-a/b)x + (c/b).

  • The coefficient of x, -a/b, is the gradient m.
  • The constant term, c/b, is the y-intercept.
3

Example: Finding Gradient and Y-Intercept

Consider the equation 5x + 4y = 8. To find the gradient and y-intercept:

Rearrange to solve for y: 4y = -5x + 8 Divide both sides by 4: y = (-5/4)x + 2

  • Gradient m = -5/4.
  • Y-intercept c = 2, meaning the line crosses the y-axis at (0, 2).
4

Determining Gradient and Y-Intercept from a Graph

From a graph, the gradient (m) is the ratio of the vertical change (rise) to the horizontal change (run) between any two distinct points on the line:

\[ m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1} \]

The y-intercept is the y-coordinate where the line crosses the y-axis (where x = 0). This point is written as (0, c).

  • Choose two clear points on the line to calculate the gradient.
  • Locate the point where the line meets the y-axis to find the y-intercept.
5

Simplifying Equations Fully

Always express the equation of a line in its simplest form:

Coefficients should be integers with no common factors (unless fractions are preferred).

The equation should be rearranged neatly, typically with y isolated on one side for slope-intercept form or with integer coefficients in standard form.

  • Simplification improves clarity and reduces errors in interpretation.
  • For example, 10x + 8y = 16 can be simplified by dividing all terms by 2 to get 5x + 4y = 8.

At-a-glance summary

Comparison table

StepDetailExampleExam Use
Identify formCheck if equation is standard (ax + by = c) or slope-intercept (y = mx + c)5x + 4y = 8 is standard formRecognise form to decide rearrangement method
RearrangeSolve for y to get slope-intercept form if neededFrom 5x + 4y = 8, rearranged to y = (-5/4)x + 2Find gradient and y-intercept clearly
Calculate gradientGradient m = coefficient of x in slope-intercept formm = -5/4State gradient precisely for marks
Find y-interceptY-intercept c = constant term in slope-intercept formc = 2Identify point where line crosses y-axis
From graphCalculate rise/run between two points; read y-intercept at x=0Points (2, -0.5) and (0, 2) give m = (-0.5 - 2)/(2 - 0) = -2.5/2 = -1.25Use graph to verify or find equation components
SimplifyReduce coefficients to simplest integer ratio or simplest fraction10x + 8y = 16 simplified to 5x + 4y = 8Avoid losing marks for unsimplified answers

Active recall

Quick check

1. Given the equation 3x + 6y = 12, what is the gradient and y-intercept?

Rearrange: 6y = -3x + 12, so y = (-3/6)x + 12/6 = (-1/2)x + 2. Gradient m = -1/2, y-intercept c = 2.

2. From a graph, two points on a line are (1, 3) and (4, 9). What is the gradient?

Gradient m = (9 - 3) / (4 - 1) = 6 / 3 = 2.

3. If a line crosses the y-axis at (0, -4), what is the y-intercept?

The y-intercept is -4.

4. Simplify the equation 8x + 12y = 20 before finding the gradient.

Divide all terms by 4: 2x + 3y = 5. Then rearrange to y = (-2/3)x + 5/3.

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