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Cambridge IGCSE Mathematics revision notes

Circle theorems I Revision Notes

Cambridge IGCSE revision notes for Circle theorems I.

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revision notes

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Circle theorems I

CambridgeIGCSEMathematicsExtended Geometry

Complete revision guide

Determining Unknown Angles Using Key Circle Theorems

This note explains how to find unknown angles in circle diagrams by applying six fundamental circle theorems. Each theorem is presented with reasoning, original examples, and guidance on justifying answers in exam contexts.

Syllabus source

Section 3, Topic E4.7, page 48, objective E4.7.1

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What you should be able to do

  • ✓Understand and apply the angle in a semicircle theorem.
  • ✓Use the perpendicularity of tangent and radius to find angles.
  • ✓Relate the angle at the centre to the angle at the circumference.
  • ✓Identify equal angles in the same segment of a circle.
  • ✓Apply the property of opposite angles in cyclic quadrilaterals summing to 180°.“Use the alternate segment theorem to connect tangent-chord angles with angles inside the circle.
1

Angle in a Semicircle is 90°

When a triangle is formed by a diameter of a circle and any point on the circle, the angle opposite the diameter is always a right angle (90°). This is because the diameter subtends a semicircle, and the inscribed angle on a semicircle is a right angle.

To use this theorem, identify the diameter and the point on the circle forming the triangle. The angle at that point is 90°, which helps find unknown angles or confirm right angles in problems.

  • If AB is a diameter and C lies on the circle, then ∠ACB = 90°.
  • This theorem is useful for proving triangles are right-angled in circle problems.
2

Tangent and Radius are Perpendicular

A tangent touches a circle at exactly one point. The radius drawn to the point of contact is perpendicular to the tangent line, forming a 90° angle.

This property allows you to find unknown angles involving tangents by recognising right angles where the radius meets the tangent.

For example, if a tangent touches the circle at point T and the centre is O, then ∠OTTangent = 90°. This can be used to calculate adjacent angles in the diagram.

  • Tangent at point T and radius OT satisfy ∠OTTangent = 90°.
  • Use this to find unknown angles adjacent to the tangent or radius.
3

Angle at the Centre is Twice the Angle at the Circumference

An arc of a circle subtends two angles: one at the centre and one at the circumference. The angle at the centre is always twice the angle at the circumference subtended by the same arc.

This relationship helps find unknown angles when both centre and circumference angles are involved.

For example, if arc AB subtends ∠AOB at the centre and ∠ACB at the circumference, then ∠AOB = 2 × ∠ACB.

  • If ∠ACB = 30°, then ∠AOB = 60°.
  • Use this to relate central and inscribed angles for calculations.
4

Angles in the Same Segment are Equal

Angles subtended by the same chord and on the same side of the chord are equal. This means if two points lie on the circumference on the same side of a chord, the angles they form with the chord are equal.

This property is useful for finding unknown angles or proving angle equality in circle problems.

For example, if chord AB subtends angles ∠ACB and ∠ADB on the same segment, then ∠ACB = ∠ADB.

  • Angles subtended by the same chord in the same segment are equal.
  • Use this to find missing angles or prove angle relationships.
5

Opposite Angles of a Cyclic Quadrilateral Sum to 180°

A cyclic quadrilateral is a four-sided figure with all vertices on the circle. The opposite angles of such a quadrilateral add up to 180° (are supplementary).

This property helps find unknown angles inside cyclic quadrilaterals and is often used to justify angle sums.

For example, in cyclic quadrilateral ABCD, ∠A + ∠C = 180° and ∠B + ∠D = 180°.

  • Opposite angles in cyclic quadrilaterals sum to 180°.
  • Use this to calculate unknown angles or verify cyclic quadrilaterals.
6

Alternate Segment Theorem

This theorem links the angle between a tangent and a chord at the point of contact to the angle in the alternate segment of the circle.

Specifically, the angle between the tangent and chord equals the angle subtended by the chord in the opposite segment of the circle.

For example, if a tangent touches the circle at point A and chord AB is drawn, then the angle between the tangent and chord at A equals the angle subtended by chord AB in the alternate segment (not containing the tangent).

  • Angle between tangent and chord = angle in alternate segment.
  • Use this to find unknown angles involving tangents and chords.

At-a-glance summary

Comparison table

StepDetailExampleExam Use
Identify the theoremLook for key features: diameter, tangent, centre, chord, cyclic quadrilateral.A triangle with a diameter and a point on the circle suggests angle in semicircle.Recognising the correct theorem guides correct angle calculation and justification.
Apply the theoremUse the property to write an equation relating known and unknown angles.If ∠ACB is unknown but AB is diameter, then ∠ACB = 90°.Write angle relationships clearly to earn method marks.
Calculate unknown angleSubstitute known values and solve for the unknown.If ∠AOB = 80°, then ∠ACB = 40° (half of centre angle).Show substitution and reasoning to gain full marks.
Justify your answerState the theorem used and why it applies.'Angle in a semicircle is 90° because AB is diameter.'Explicit justification is required for full marks.

Active recall

Quick check

1. What is the angle formed by a diameter and a point on the circle?

It is 90° because the angle in a semicircle is a right angle.

2. If the angle at the centre is 100°, what is the angle at the circumference subtended by the same arc?

50°, since the angle at the centre is twice the angle at the circumference.

3. In a cyclic quadrilateral, one angle is 70°. What is its opposite angle?

110°, because opposite angles in a cyclic quadrilateral sum to 180°.

4. What is the angle between a tangent and radius at the point of contact?

90°, the tangent is perpendicular to the radius at the point of contact.

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