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Cambridge IGCSE Physics revision notes

Gases and the absolute scale of temperature Revision Notes

Cambridge IGCSE revision notes for Gases and the absolute scale of temperature.

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Gases and the absolute scale of temperature

CambridgeIGCSEPhysicsThermal physics

Complete revision guide 1 of 3

Pressure Changes in a Fixed Amount of Gas with Temperature and Volume Using Particle Theory

This note explains how the pressure of a fixed amount of gas varies with temperature at constant volume and with volume at constant temperature, using particle theory. It covers the physical reasons behind these changes, relevant gas laws, and how to represent these relationships graphically and conceptually.

Syllabus source

Section 3, Topic 2.1.3, page 19, objective 2.1.3.1

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What you should be able to do

  • ✓Understand how gas pressure changes with temperature at constant volume.
  • ✓Explain how gas pressure changes with volume at constant temperature.
  • ✓Apply particle theory to explain these pressure changes.
  • ✓Use relevant gas laws to describe pressure-volume and pressure-temperature relationships.
  • ✓Interpret graphs showing pressure versus temperature and pressure versus volume for a fixed amount of gas.
1

Particle Theory and Gas Pressure

A gas consists of a large number of tiny particles (atoms or molecules) moving randomly in all directions. These particles collide with each other and with the walls of their container.

Pressure is the force exerted per unit area by gas particles colliding with the container walls. It depends on the frequency and force of these collisions.

The kinetic energy of gas particles is directly related to temperature: as temperature increases, particles move faster and collide more forcefully, increasing pressure if volume is constant.

  • Gas particles move randomly and collide with container walls.
  • Pressure arises from these collisions.
  • Higher particle speed means more forceful collisions and higher pressure.
2

Pressure and Temperature at Constant Volume (Gay-Lussac's Law)

When the volume of a gas is fixed, increasing the temperature increases the average kinetic energy of the particles.

Faster particles collide more frequently and with greater force against the container walls, causing the pressure to rise.

This relationship is directly proportional: pressure (p) is proportional to absolute temperature (T) when volume (V) and amount of gas are constant, expressed as p ∝ T (at constant V).

  • Pressure increases as temperature increases at constant volume.
  • Particle kinetic energy increases with temperature.
  • More energetic collisions cause higher pressure.
3

Pressure and Volume at Constant Temperature (Boyle's Law)

At constant temperature, the average kinetic energy of gas particles remains unchanged.

If the volume of the gas decreases, particles have less space to move, so they collide more frequently with the container walls, increasing pressure.

Conversely, increasing volume decreases collision frequency and pressure decreases accordingly, showing an inverse relationship: p ∝ 1/V (at constant T).

  • Pressure is inversely proportional to volume at constant temperature.
  • Smaller volume means more frequent collisions and higher pressure.
  • Larger volume means fewer collisions and lower pressure.
4

Relevant Gas Laws and Equations

Gay-Lussac's Law: For a fixed mass of gas at constant volume, pressure is directly proportional to absolute temperature: p/T = constant.

Boyle's Law: For a fixed mass of gas at constant temperature, pressure multiplied by volume is constant: pV = constant.

These laws assume the amount of gas and the temperature or volume are held constant as specified.

  • p/T = constant (constant volume)
  • pV = constant (constant temperature)
  • Temperature must be in kelvin for these laws to apply.
5

Graphical Representation and Interpretation

A graph of pressure (y-axis, in pascals) against temperature (x-axis, in kelvin) at constant volume is a straight line passing through the origin, showing direct proportionality.

A graph of pressure (y-axis) against volume (x-axis, in cubic metres) at constant temperature is a hyperbola, showing inverse proportionality.

The gradient of the pressure-temperature graph indicates how pressure changes per unit temperature increase, while the area under the curve is not physically meaningful in this context.

  • Pressure vs Temperature graph: straight line through origin (constant volume).
  • Pressure vs Volume graph: hyperbola (constant temperature).
  • Gradient shows rate of pressure change with temperature.

At-a-glance summary

Comparison table

ConditionPhysical ExplanationGas LawGraph Shape
Constant VolumeTemperature increase raises particle speed and collision force, increasing pressurep/T = constantStraight line (pressure vs temperature)
Constant TemperatureVolume decrease increases collision frequency, raising pressurepV = constantHyperbola (pressure vs volume)
Increasing Temperature at Constant VolumeParticles move faster, collide more forcefully, pressure risesp ∝ TLinear increase
Increasing Volume at Constant TemperatureParticles collide less often, pressure decreasesp ∝ 1/VInverse curve

Active recall

Quick check

1. What happens to the pressure of a fixed amount of gas if its temperature increases at constant volume?

The pressure increases because particles move faster and collide more forcefully with the container walls.

2. How does pressure change when the volume of a gas is doubled at constant temperature?

The pressure halves because particles have more space and collide less frequently with the walls.

3. Write the gas law that relates pressure and temperature at constant volume.

p/T = constant (pressure is directly proportional to absolute temperature).

4. What is the shape of the graph of pressure against volume at constant temperature?

A hyperbola showing inverse proportionality between pressure and volume.

Complete revision guide 2 of 3

Converting Temperatures Between Kelvin and Degrees Celsius

This note explains the relationship between the Kelvin and Celsius temperature scales, how to convert temperatures between them using the formula T(K) = T(°C) + 273, and includes a worked example demonstrating the conversion process. It also clarifies the physical meaning of the Kelvin scale and common errors to avoid.

Syllabus source

Section 3, Topic 2.1.3, page 19, objective 2.1.3.2

Open source document ↗

What you should be able to do

  • ✓Understand the Kelvin and Celsius temperature scales and their relationship.
  • ✓Use the formula T(K) = T(°C) + 273 to convert temperatures from Celsius to Kelvin.
  • ✓Convert temperatures from Kelvin to Celsius by rearranging the formula.
  • ✓Recognise the significance of absolute zero and the Kelvin scale as an absolute temperature scale.
  • ✓Apply temperature conversions correctly in physics calculations.
1

Temperature Scales: Celsius and Kelvin

Temperature is a measure of the average kinetic energy of the particles in a substance. The Celsius (°C) scale is commonly used in everyday life and is based on the freezing point of water at 0 °C and boiling point at 100 °C under standard atmospheric pressure.

The Kelvin (K) scale is the absolute temperature scale used in physics. It starts at absolute zero, the theoretical temperature at which particles have minimum kinetic energy and molecular motion nearly stops. Absolute zero is 0 K, which corresponds to −273.15 °C.

The Kelvin scale is important because many gas laws and thermodynamic equations require temperature to be measured from absolute zero to avoid negative values and to maintain proportionality with kinetic energy.

  • Celsius scale: 0 °C = freezing point of water, 100 °C = boiling point of water.
  • Kelvin scale: 0 K = absolute zero (−273.15 °C).
  • Kelvin is an absolute scale; Celsius is relative to water's phase changes.
2

Converting Between Celsius and Kelvin

The relationship between temperature in degrees Celsius (T(°C)) and temperature in Kelvin (T(K)) is linear and given by the formula:

\[ T(K) = T(°C) + 273 \] This means to convert a temperature from Celsius to Kelvin, add 273.

To convert from Kelvin to Celsius, rearrange the formula: \[ T(°C) = T(K) - 273 \] This means subtract 273 from the Kelvin temperature to get degrees Celsius.

  • Formula: T(K) = T(°C) + 273
  • Rearranged: T(°C) = T(K) - 273
  • Always use Kelvin in gas law calculations to avoid negative temperatures.
3

Worked Example: Converting Celsius to Kelvin

Convert 25 °C to Kelvin using the formula. Step 1: Write down the formula: \[ T(K) = T(°C) + 273 \] Step 2: Substitute the known value: \[ T(K) = 25 + 273 \] Step 3: Calculate the sum: \[ T(K) = 298 \] Step 4: Write the answer with units: 25 °C = 298 K.

Common error: Using 273.15 instead of 273 or forgetting to add 273, which leads to incorrect temperature values. For IGCSE level, adding 273 is accepted and sufficient.

  • Formula: T(K) = T(°C) + 273
  • Substitution: T(K) = 25 + 273
  • Answer: T(K) = 298 K
  • Common error: Forgetting to add 273 or subtracting incorrectly.
4

Physical Significance of the Kelvin Scale

The Kelvin scale is absolute because it starts at absolute zero, the lowest possible temperature where particles have minimum kinetic energy. This makes it essential for scientific calculations involving gases and thermodynamics, where temperature must be proportional to particle energy.

Unlike Celsius, Kelvin temperatures cannot be negative. This avoids confusion in calculations and ensures all temperatures are positive values, which is important for laws such as the ideal gas law.

Absolute zero is approximately −273.15 °C, but for IGCSE calculations, 273 is used for simplicity.

  • 0 K = absolute zero, no molecular motion.
  • Kelvin scale is absolute and non-negative.
  • Used in gas laws and thermodynamics for proportionality with kinetic energy.
5

Summary and Key Points

The Celsius scale is based on water's freezing and boiling points; the Kelvin scale is absolute, starting at absolute zero.

To convert Celsius to Kelvin, add 273: \( T(K) = T(°C) + 273 \).

To convert Kelvin to Celsius, subtract 273: \( T(°C) = T(K) - 273 \). Kelvin is essential in physics because it relates directly to particle kinetic energy and avoids negative temperatures in calculations.

  • Kelvin and Celsius scales differ by 273 units.
  • Use Kelvin in physics calculations involving temperature.
  • Remember the formula and its rearrangement for conversions.

At-a-glance summary

Comparison table

StepPhysics DetailEvidenceExam Use
Identify temperature scaleKnow if temperature is in °C or KGiven in question or contextEnsures correct formula application
Convert °C to KAdd 273 to °C valueFormula: T(K) = T(°C) + 273Marks for correct substitution and calculation
Convert K to °CSubtract 273 from K valueRearranged formula: T(°C) = T(K) - 273Marks for correct rearrangement and answer
Use Kelvin in calculationsKelvin is absolute scale, needed for gas lawsPhysics principle of absolute zeroAvoids negative temperatures, essential for correct answers
Check unitsInclude units K or °C in final answerUnits given in question or standardUnits required for full marks

Active recall

Quick check

1. What is the Kelvin temperature equivalent to 0 °C?

0 °C + 273 = 273 K.

2. Convert 310 K to degrees Celsius.

310 K - 273 = 37 °C.

3. Why is the Kelvin scale used in gas law calculations?

Because it is an absolute scale starting at absolute zero, ensuring temperature is proportional to particle kinetic energy and avoiding negative values.

Complete revision guide 3 of 3

Pressure-Volume Relationship for a Fixed Mass of Gas at Constant Temperature

This note explains the inverse relationship between pressure and volume for a fixed amount of gas kept at constant temperature, expressed by the equation pV = constant. It covers the physical basis of this relationship, how to use the equation in calculations, and how to represent it graphically.

Syllabus source

Section 3, Topic 2.1.3, page 19, objective 2.1.3.3

Open source document ↗

What you should be able to do

  • ✓Understand that for a fixed mass of gas at constant temperature, pressure and volume are inversely proportional.
  • ✓Use the equation pV = constant to solve problems involving pressure and volume changes.
  • ✓Represent the pressure-volume relationship graphically and interpret the shape of the graph.
1

1. The Pressure-Volume Relationship for Gases

For a fixed mass of gas at constant temperature (an isothermal process), the pressure (p) and volume (V) of the gas are related such that their product remains constant. This means that if the volume increases, the pressure decreases proportionally, and vice versa.

Mathematically, this is expressed as: p × V = constant

This relationship is known as Boyle's Law. It applies only when the temperature and the amount of gas remain unchanged. The pressure is measured in pascals (Pa) or newtons per square metre (N/m²), and volume is measured in cubic metres (m³) or litres (L).

  • pV = constant for a fixed mass of gas at constant temperature.
  • Pressure and volume are inversely proportional under these conditions.
  • Units: pressure in pascals (Pa), volume in cubic metres (m³) or litres (L).
2

2. Physical Explanation Using Particle Theory

Gas pressure arises from gas particles colliding with the walls of their container. When the volume decreases, the gas particles have less space to move, so they collide more frequently with the container walls, increasing the pressure.

Conversely, increasing the volume gives particles more space, reducing collision frequency and pressure.

Since temperature is constant, the average kinetic energy of the particles remains unchanged, so the change in pressure is solely due to the change in collision frequency caused by volume change.

  • Pressure results from particle collisions with container walls.
  • Decreasing volume increases collision frequency and pressure.
  • Increasing volume decreases collision frequency and pressure.
  • Temperature constant means average kinetic energy of particles is constant.
3

3. Using the Equation pV = Constant in Calculations

If a gas changes from an initial state (p₁, V₁) to a final state (p₂, V₂) at constant temperature, the equation can be written as: p₁V₁ = p₂V₂

This allows calculation of an unknown pressure or volume when the other three quantities are known.

Example calculation: A gas at 200 kPa occupies 0.5 m³. If the volume is compressed to 0.2 m³ at constant temperature, find the new pressure p₂.

  • Use p₁V₁ = p₂V₂ for changes at constant temperature.
  • Rearranged to find unknown: p₂ = (p₁V₁) / V₂ or V₂ = (p₁V₁) / p₂.
  • Example: p₂ = (200000 Pa × 0.5 m³) / 0.2 m³ = 500000 Pa = 500 kPa.
4

4. Graphical Representation of the Pressure-Volume Relationship

Plotting pressure (p) on the vertical axis (y-axis) and volume (V) on the horizontal axis (x-axis) for a fixed mass of gas at constant temperature produces a curve called an isotherm.

The graph is a rectangular hyperbola, showing that pressure decreases as volume increases.

The area under the curve between two volumes does not have a direct physical meaning in this context, but the shape clearly shows the inverse relationship: doubling the volume halves the pressure, and so on.

  • Graph axes: pressure (Pa) on y-axis, volume (m³) on x-axis.
  • Graph shape: rectangular hyperbola (inverse proportionality).
  • As volume increases, pressure decreases.
  • Curve is called an isotherm (constant temperature).
5

5. Practical Considerations and Accuracy

In experiments to verify pV = constant, a sealed syringe or a gas-filled container with a movable piston can be used to vary volume and measure pressure.

Variables: independent variable is volume, dependent variable is pressure, temperature is kept constant (e.g., by performing the experiment at room temperature and allowing time for thermal equilibrium).

Measurements should be repeated to improve accuracy and identify anomalies. Use precise pressure gauges and volume markings for better results.

  • Use apparatus like a syringe with pressure sensor to vary volume and measure pressure.
  • Keep temperature constant during measurements.
  • Repeat measurements for reliability.
  • Use accurate instruments to reduce uncertainty.

At-a-glance summary

Comparison table

StepPhysics DetailEvidenceExam Use
1State initial and final pressure and volume valuesGiven or measured values in problem or experimentIdentify known and unknown quantities for calculation
2Apply p₁V₁ = p₂V₂ for constant temperatureBoyle's Law for fixed mass of gasCalculate unknown pressure or volume
3Rearrange formula to isolate unknown variableAlgebraic manipulationSolve for required quantity
4Substitute values with correct unitsUse pascals for pressure, cubic metres or litres for volumeEnsure unit consistency for correct answer
5Calculate and include units in final answerComplete calculation with unitsGain full marks by correct numerical answer and units

Active recall

Quick check

1. What happens to the pressure of a fixed mass of gas at constant temperature if the volume is doubled?

The pressure is halved because pressure and volume are inversely proportional (pV = constant).

2. Write the formula relating initial and final pressure and volume for a gas at constant temperature.

p₁V₁ = p₂V₂.

3. On a graph of pressure against volume for a fixed mass of gas at constant temperature, what is the shape of the curve?

A rectangular hyperbola, showing inverse proportionality between pressure and volume.

4. If a gas at 100 kPa occupies 0.3 m³ and is compressed to 0.1 m³ at constant temperature, what is the new pressure?

p₂ = (p₁V₁) / V₂ = (100000 Pa × 0.3 m³) / 0.1 m³ = 300000 Pa = 300 kPa.

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