Identifying All Possible Outcomes
In any simple probability scenario, the first step is to list every possible outcome that can occur. This is essential because probabilities are assigned to these outcomes, and none should be omitted. For example, when rolling a fair six-sided die, the possible outcomes are the numbers 1, 2, 3, 4, 5, and 6. Each outcome is mutually exclusive, meaning only one can occur at a time, and collectively exhaustive, meaning one of them must occur.
- List outcomes carefully to avoid missing any.
- Ensure outcomes are mutually exclusive and collectively exhaustive.
Calculating Probabilities for Each Outcome
Once all outcomes are identified, calculate the probability of each. The probability of an outcome is the chance that it will occur, expressed as a number between 0 and 1. For equally likely outcomes, the probability is 1 divided by the number of outcomes. For example, with a fair six-sided die, each outcome has probability 1/6 ≈ 0.1667. If outcomes are not equally likely, probabilities must be assigned based on the context or given data, ensuring they are valid (between 0 and 1).
- Probability of an outcome = (Number of favourable outcomes) / (Total number of possible outcomes) for equally likely cases.
- Probabilities must be between 0 and 1 inclusive.
Ensuring the Sum of Probabilities Equals One
A fundamental property of probability distributions is that the sum of the probabilities of all possible outcomes must be exactly 1. This reflects the certainty that one of the possible outcomes will occur. After calculating individual probabilities, add them together to check this condition. If the sum is not 1, re-examine the calculations or the list of outcomes for errors.
- Sum all probabilities: P(outcome 1) + P(outcome 2) +... + P(outcome n) = 1.
- If sum ≠ 1, check for missing outcomes or calculation mistakes.
Presenting the Probability Distribution in Tabular Form
To communicate the probabilities clearly, organise the outcomes and their probabilities into a probability distribution table. This table has two columns: one for the outcomes and one for their corresponding probabilities. This format makes it easier to interpret and use the probabilities for further calculations or analysis. For example, the distribution for a fair six-sided die is:
| Outcome | Probability |\n|---------|-------------|\n| 1 | 1/6 |\n| 2 | 1/6 |\n| 3 | 1/6 |\n| 4 | 1/6 |\n| 5 | 1/6 |\n| 6 | 1/6 |
- Use a two-column table: outcomes and probabilities.
- Ensure probabilities are expressed as fractions, decimals, or percentages consistently.
- Check that the table covers all outcomes and sums to 1.
Worked Example: Tossing a Fair Coin Twice
Consider tossing a fair coin twice. The possible outcomes are: HH (both heads), HT (head then tail), TH (tail then head), and TT (both tails). Each outcome is equally likely with probability 1/4.
Step 1: List outcomes: HH, HT, TH, TT.\nStep 2: Calculate probabilities: each is 1/4 = 0.25.\nStep 3: Sum probabilities: 0.25 + 0.25 + 0.25 + 0.25 = 1.\nStep 4: Present in a table:
| Outcome | Probability |\n|---------|-------------|\n| HH | 0.25 |\n| HT | 0.25 |\n| TH | 0.25 |\n| TT | 0.25 |
- List all outcomes explicitly.
- Calculate and verify probabilities.
- Display in a clear table format.
At-a-glance summary
Comparison table
| Step | Detail | Example | Exam Use |
|---|---|---|---|
| Identify outcomes | List all possible mutually exclusive and exhaustive outcomes | Rolling a die: outcomes 1 to 6 | Always list all outcomes to avoid missing any marks |
| Calculate probabilities | Assign probability to each outcome, ensuring values between 0 and 1 | Each die face has probability 1/6 | Show correct fractions or decimals for full marks |
| Check sum | Sum all probabilities to confirm they equal 1 | Sum of 6 outcomes: 6 × 1/6 = 1 | Write sum explicitly to demonstrate understanding |
| Present distribution | Create a table with outcomes and their probabilities | Table showing die faces and probabilities | Use clear tables to organise answers and gain presentation marks |
Active recall
Quick check
1. What must the sum of all probabilities in a distribution be?
The sum must be exactly 1, representing certainty that one outcome will occur.
2. If a fair six-sided die is rolled, what is the probability of rolling a 4?
The probability is 1/6, since all six outcomes are equally likely.
3. Why is it important to list all possible outcomes?
To ensure the probability distribution is complete and the total probability sums to 1.
4. How should probabilities be presented in a probability distribution?
In a table with two columns: one for outcomes and one for their corresponding probabilities.
