Question detail
In the redox reaction between zinc and copper(II) sulfate, zinc is oxidised to zinc ions. Write the half equation for the oxidation of zinc, including the oxidation states.
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At a glance
Question
Type
exam_style
Style
Topic
Oxidation, reduction and redox equations
Question
In the redox reaction between zinc and copper(II) sulfate, zinc is oxidised to zinc ions. Write the half equation for the oxidation of zinc, including the oxidation states.
Answer
Zn(s) → Zn²⁺(aq) + 2e⁻; Oxidation state of Zn changes from 0 to +2.
Explanation
This answer is strong because it correctly identifies the oxidation process of zinc, showing the loss of electrons and the change in oxidation state. The question tests the understanding of half equations and oxidation states in redox reactions.
Common mistake
Balancing Redox Equations Mistake
Students often forget to balance both the number of atoms and the charges in redox equations, leading to incorrect final equations.
To balance a redox equation, first separate the oxidation and reduction half-equations. Ensure that both the number of atoms and the total charge are equal on both sides. For example, in the half-equation for the reduction of MnO4- to Mn2+, balance the manganese and oxygen atoms, then balance the charges by adding electrons. This ensures the final redox equation is accurate.
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