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Thermodynamics (A-level only)

This A-level-only topic extends energetics into lattice enthalpy, entropy and thermodynamic feasibility.

9

Objectives

45

Flashcards

44

Questions

90 min

Study time

AQAA LevelChemistryPhysical chemistry

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9 objective pages available

Born-Haber cycles (A-level only)4 objectives
  • Construct Born-Haber cycles for ionic compounds.
  • Calculate lattice enthalpy from Born-Haber data.
  • Compare experimental and theoretical lattice enthalpies.
  • Use lattice enthalpy comparisons to infer covalent character.
Entropy and Gibbs free energy (A-level only)5 objectives
  • Explain entropy as a measure of dispersal of energy or disorder.
  • Calculate entropy changes from standard entropy data.
  • Use ΔG = ΔH - TΔS to calculate Gibbs free energy change.
  • Predict whether a reaction is feasible from Gibbs free energy.
  • Explain why feasibility does not guarantee an observable reaction rate.

Key terms

Born–Haber cycleLattice enthalpylattice enthalpyBorn-Haber cycleExperimental Lattice EnthalpyTheoretical Lattice Enthalpycovalent characterentropyGibbs free energyentropy changestandard entropy dataGibbs free energy change

Exam tips

  • Constructing Born-Haber Cycles: When constructing a Born-Haber cycle, start by identifying the enthalpy changes involved in the formation of the ionic compound from its elements. Use Hess's law to relate these changes.
  • Calculating Lattice Enthalpy: Use the Born-Haber cycle to calculate lattice enthalpy by summing the enthalpy changes for each step.

Common mistakes

  • Incorrect Born-Haber Cycle Construction: To correctly construct a Born-Haber cycle, include all necessary enthalpy changes: the enthalpy of formation, sublimation, ionization, and electron affinity. For example, use the formula: ΔH_f = ΔH_sublimation + ΔH_ionization + ΔH_electron_affinity + ΔH_lattice. Substitute the values for each enthalpy change, perform the calculations, and ensure all steps are represented in the cycle.
  • Incorrect Lattice Enthalpy Calculation: To fix this, remember that lattice enthalpy is exothermic and should be treated as a negative value in calculations. Use the formula: Lattice Enthalpy = ΔHf (formation enthalpy) - (ΔHsub + ΔHionization + ΔHelectron + ΔHbond). Substitute the values correctly, ensuring to apply the negative sign for lattice enthalpy. For example, if ΔHf = -400 kJ/mol, ΔHsub = +100 kJ/mol, ΔHionization = +200 kJ/mol, ΔHelectron = -100 kJ/mol, and ΔHbond = +50 kJ/mol, the calculation would be: Lattice Enthalpy = -400 - (100 + 200 - 100 + 50) = -400 - 250 = -650 kJ/mol. Thus, the lattice enthalpy is -650 kJ/mol.

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Thermodynamics (A-level only) Revision - AQA Chemistry 7405 | ExamCompanion