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Cambridge IGCSE Chemistry revision notes

Giant covalent structures Revision Notes

Cambridge IGCSE revision notes for Giant covalent structures.

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Giant covalent structures

CambridgeIGCSEChemistryAtoms, elements and compounds

Complete revision guide 1 of 4

Giant Covalent Structures in Graphite and Diamond

Graphite and diamond are allotropes of carbon exhibiting giant covalent structures that determine their distinct physical properties. Graphite consists of layers of hexagonally arranged carbon atoms bonded to three others, allowing layers to slide and making it soft and slippery. Diamond features a three-dimensional tetrahedral network where each carbon atom bonds covalently to four others, resulting in exceptional hardness and a very high melting point.

Syllabus source

Section 3, Topic 2.6, page 14, objective 2.6.1

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What you should be able to do

  • ✓Describe the atomic arrangement and bonding in graphite and diamond.
  • ✓Explain how the structure of graphite leads to its physical properties such as softness and electrical conductivity.
  • ✓Explain how the structure of diamond leads to its hardness and high melting point.
  • ✓Distinguish between the bonding and structure of graphite and diamond to account for their differing properties.
1

Atomic Structure and Bonding in Diamond

Diamond is a giant covalent structure composed entirely of carbon atoms.

Each carbon atom forms four strong covalent bonds with four other carbon atoms arranged tetrahedrally.

This creates a rigid three-dimensional network extending throughout the crystal lattice, with bond angles of approximately 109.5° between bonds (tetrahedral geometry).

  • Each carbon atom uses sp³ hybrid orbitals to form four sigma (σ) bonds.
  • The strong covalent bonds require a large amount of energy to break, resulting in diamond's high melting point (about 3550°C).
  • No free electrons are present, so diamond does not conduct electricity.
2

Atomic Structure and Bonding in Graphite

Graphite is another giant covalent structure of carbon atoms, but arranged differently from diamond.

Each carbon atom bonds covalently to three others in a planar hexagonal lattice, forming flat layers.

The fourth valence electron of each carbon atom is delocalised and free to move within the layers.

  • The layers are held together by weak van der Waals forces, allowing them to slide over each other easily, making graphite soft and slippery.
  • The delocalised electrons enable graphite to conduct electricity along the planes.
  • The bond angles within the layers are approximately 120°, consistent with trigonal planar geometry (sp² hybridisation).
3

Comparison of Physical Properties and Their Structural Causes

Diamond is extremely hard due to its strong covalent bonds in all directions, making it useful for cutting tools.

Graphite is soft and slippery because the layers can slide over each other due to weak interlayer forces.

Diamond has a very high melting point because breaking the extensive covalent network requires a lot of energy.

  • Graphite conducts electricity due to delocalised electrons; diamond does not conduct electricity.
  • Graphite's layered structure results in anisotropic properties, with conductivity and softness along layers but not between them.
  • Both substances are insoluble in water and most solvents due to the strength of their covalent bonds.
4

Structural Representations and Formulae

Diamond's structure can be represented by a three-dimensional tetrahedral network of carbon atoms, each bonded to four others.

Graphite's structure is represented by layers of hexagonal rings of carbon atoms, with delocalised electrons above and below the planes.

  • Empirical formula for both is C, as they are allotropes of carbon.
  • No simple molecular formula exists due to the giant covalent nature.
  • Structural diagrams show the difference between tetrahedral bonding in diamond and planar hexagonal bonding in graphite.
5

Worked Example: Explaining Differences in Melting Points

Diamond has a melting point around 3550°C, whereas graphite sublimes at about 3900°C.

Both have high melting points due to strong covalent bonds, but graphite's layers can separate more easily than breaking diamond's 3D network.

  • Melting diamond requires breaking all covalent bonds in the 3D network.
  • Graphite's melting involves overcoming weaker van der Waals forces between layers, but the covalent bonds within layers remain intact.
  • This explains why graphite sublimes rather than melts under normal pressure.

At-a-glance summary

Comparison table

PropertyDiamondGraphite
Atomic bondingEach carbon atom covalently bonded to 4 others (tetrahedral)Each carbon atom covalently bonded to 3 others (planar hexagonal)
Structure3D rigid networkLayers of hexagonal sheets
Bonding electronsAll electrons involved in sigma bondsOne electron per carbon delocalised between layers
Electrical conductivityDoes not conduct (no free electrons)Conducts electricity along layers (due to delocalised electrons)
HardnessVery hard (strong bonds in all directions)Soft and slippery (layers slide easily)
Melting pointVery high (~3550°C)Very high (~3900°C, sublimes)

Active recall

Quick check

1. How many covalent bonds does each carbon atom form in diamond?

Four covalent bonds arranged tetrahedrally.

2. Why can graphite conduct electricity but diamond cannot?

Graphite has delocalised electrons free to move within layers; diamond has no free electrons.

3. What causes graphite to be soft and slippery?

Weak van der Waals forces between layers allow them to slide over each other.

4. What is the shape around each carbon atom in graphite?

Trigonal planar with bond angles of about 120°.

Complete revision guide 2 of 4

Connecting the Structures and Bonding of Graphite and Diamond to Their Applications

This note explains how the distinct giant covalent structures and bonding in graphite and diamond determine their specific applications: graphite as a lubricant and electrode, and diamond in cutting tools. The layered hexagonal arrangement in graphite allows layers to slide, enabling lubrication and electrical conductivity, while the tetrahedral network in diamond results in exceptional hardness suitable for cutting.

Syllabus source

Section 3, Topic 2.6, page 14, objective 2.6.2

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What you should be able to do

  • ✓Describe the giant covalent structures of graphite and diamond.
  • ✓Explain how the bonding and structure of graphite relate to its use as a lubricant and electrode.
  • ✓Explain how the bonding and structure of diamond relate to its use in cutting tools.
  • ✓Relate physical properties arising from structure to practical applications.
1

Structure and Bonding in Graphite

Graphite is a giant covalent structure composed entirely of carbon atoms. Each carbon atom forms three strong covalent bonds with three other carbon atoms in the same plane, creating hexagonal rings arranged in layers.

Within each layer, the carbon atoms are bonded by strong covalent bonds, forming a two-dimensional hexagonal lattice. The fourth outer electron of each carbon atom is delocalised and free to move within the layers, contributing to electrical conductivity.

The layers are held together by weak van der Waals forces, allowing them to slide easily over each other. This layered structure is responsible for graphite's lubricating properties.

  • Each carbon atom bonded to three others in hexagonal layers.
  • Delocalised electrons present within layers enable electrical conductivity.
  • Weak forces between layers allow layers to slide over each other.
2

Applications of Graphite: Lubricant and Electrode

Graphite's layered structure allows the layers to slide over one another easily, reducing friction between moving parts. This makes graphite an effective dry lubricant, especially in high-temperature or vacuum environments where liquid lubricants are unsuitable.

The presence of delocalised electrons within the layers enables graphite to conduct electricity. This property allows graphite to be used as electrodes in electrolysis and in batteries.

Graphite electrodes are used in electric arc furnaces for steel production because they can withstand high temperatures and conduct electricity efficiently.

  • Layered structure enables sliding, reducing friction (lubricant).
  • Delocalised electrons allow electrical conductivity (electrode).
  • High melting point and chemical inertness make graphite suitable for high-temperature applications.
3

Structure and Bonding in Diamond

Diamond is another giant covalent structure composed of carbon atoms. Each carbon atom forms four strong covalent bonds with four other carbon atoms arranged tetrahedrally.

This three-dimensional network of strong covalent bonds extends throughout the entire crystal, making diamond extremely hard and rigid.

There are no free electrons in diamond, so it does not conduct electricity.

  • Each carbon atom bonded to four others in a tetrahedral arrangement.
  • Strong covalent bonds throughout a 3D network.
  • No delocalised electrons; diamond is an electrical insulator.
4

Application of Diamond in Cutting Tools

The hardness of diamond arises from its strong covalent bonds in a rigid three-dimensional structure. This makes diamond the hardest naturally occurring substance.

Because of this extreme hardness, diamond is used in cutting, grinding, and drilling tools to cut or shape hard materials such as metals, glass, and stone.

Diamond-tipped cutting tools maintain a sharp edge for longer and resist wear, improving efficiency and precision in industrial applications.

  • Strong covalent bonding gives diamond exceptional hardness.
  • Used in cutting tools for hard materials due to durability and sharpness.
  • Does not conduct electricity, so not used as an electrode.
5

Summary of Structure-Property-Application Relationships

The contrasting structures of graphite and diamond explain their different physical properties and applications.

Graphite's layered structure with delocalised electrons results in lubricating properties and electrical conductivity, making it suitable as a lubricant and electrode.

Diamond's rigid tetrahedral network of covalent bonds results in extreme hardness, making it ideal for cutting tools.

  • Structure determines physical properties such as hardness and conductivity.
  • Properties determine practical applications in industry and technology.

At-a-glance summary

Comparison table

PropertyGraphiteDiamond
BondingEach carbon bonded to 3 others; 1 delocalised electron per atomEach carbon bonded to 4 others; no delocalised electrons
StructureLayers of hexagonal rings; weak forces between layers3D tetrahedral network; strong covalent bonds throughout
Electrical conductivityConducts electricity due to delocalised electronsDoes not conduct electricity
HardnessSoft and slippery due to layers slidingExtremely hard due to strong 3D bonding
UsesLubricant; electrodes in electrolysis and batteriesCutting, grinding and drilling tools

Active recall

Quick check

1. Why can graphite conduct electricity but diamond cannot?

Graphite has delocalised electrons free to move within its layers, allowing electrical conductivity; diamond has no free electrons as all are involved in covalent bonds, so it does not conduct.

2. Explain why graphite is used as a lubricant.

Graphite's layers can slide over each other easily due to weak forces between layers, reducing friction and acting as a lubricant.

3. What structural feature of diamond makes it suitable for cutting tools?

Diamond's strong covalent bonds in a rigid three-dimensional tetrahedral network make it extremely hard and durable, ideal for cutting tools.

Complete revision guide 3 of 4

Giant Covalent Structure of Silicon Dioxide (SiO₂)

Silicon dioxide (SiO₂) has a giant covalent structure consisting of a three-dimensional network of silicon and oxygen atoms bonded covalently. This structure explains its high melting and boiling points, hardness, and insolubility in water.

Syllabus source

Section 3, Topic 2.6, page 14, objective 2.6.3

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What you should be able to do

  • ✓Describe the atomic arrangement in silicon dioxide.
  • ✓Explain the bonding in silicon dioxide's giant covalent structure.
  • ✓Relate the structure to physical properties such as melting point and hardness.
  • ✓Understand why silicon dioxide is insoluble in water.
1

Atomic Structure of Silicon Dioxide

Silicon dioxide (SiO₂) is composed of silicon and oxygen atoms arranged in a continuous three-dimensional network. Each silicon atom forms covalent bonds with four oxygen atoms, arranged tetrahedrally around it. Each oxygen atom is covalently bonded to two silicon atoms, acting as a bridge between them. This arrangement repeats throughout the solid, creating a giant covalent lattice without discrete molecules.

  • Silicon atoms are at the centre of tetrahedra.
  • Each silicon atom bonds to four oxygen atoms.
  • Each oxygen atom bonds to two silicon atoms.
  • The structure extends in all directions forming a giant lattice.
2

Covalent Bonding in Silicon Dioxide

The bonds between silicon and oxygen atoms in SiO₂ are strong covalent bonds formed by the sharing of electrons. Each silicon atom shares electrons with four oxygen atoms, and each oxygen atom shares electrons with two silicon atoms. The strength and number of these covalent bonds throughout the lattice give silicon dioxide its stability and rigidity.

  • Strong covalent bonds link silicon and oxygen atoms.
  • Each bond involves shared electron pairs.
  • The network is continuous and extensive.
  • No individual SiO₂ molecules exist; it is a giant covalent structure.
3

Physical Properties Related to Structure

The giant covalent structure of silicon dioxide results in very high melting and boiling points because a large amount of energy is required to break the many strong covalent bonds throughout the lattice. Silicon dioxide is also very hard and brittle due to the rigidity of the covalent network. Additionally, it does not conduct electricity because there are no free electrons or ions to carry charge.

  • High melting point due to strong covalent bonds.
  • High boiling point for the same reason.
  • Hard and brittle solid.
  • Does not conduct electricity.
4

Solubility and Chemical Stability

Silicon dioxide is insoluble in water because the strong covalent bonds in the giant lattice are not broken by interaction with water molecules. The energy required to break these bonds is much greater than the energy released by hydration. This chemical stability makes silicon dioxide resistant to many chemical reactions under normal conditions.

  • Insoluble in water due to strong covalent bonds.
  • Stable and chemically inert under normal conditions.
  • Does not dissolve or ionise in water.
5

Summary of Silicon Dioxide Structure and Properties

Silicon dioxide's giant covalent structure consists of a continuous network of silicon and oxygen atoms linked by strong covalent bonds. This structure explains its high melting and boiling points, hardness, insolubility in water, and electrical insulating properties. Understanding this structure is essential for explaining the physical and chemical behaviour of silicon dioxide in various contexts.

  • Giant covalent lattice of Si and O atoms.
  • Strong covalent bonds throughout the structure.
  • High melting and boiling points.
  • Hard, brittle, and insoluble in water.
  • Electrical insulator.

At-a-glance summary

Comparison table

StepChemical DetailEvidenceExam Use
Atomic arrangementEach Si atom bonded to 4 O atoms tetrahedrally; each O bonded to 2 Si atomsX-ray crystallography shows tetrahedral coordinationDescribe bonding and structure accurately
Bonding typeStrong covalent bonds between Si and O atomsHigh melting point indicates strong bondsExplain physical properties from bonding
Physical propertiesHigh melting/boiling points, hardness, insolubilityExperimental melting point ~1710°C; insoluble in waterLink properties to giant covalent structure
Electrical conductivityNo free electrons or ionsSiO₂ does not conduct electricity in solid or molten stateState electrical insulating behaviour

Active recall

Quick check

1. How many oxygen atoms is each silicon atom bonded to in silicon dioxide?

Each silicon atom is bonded to four oxygen atoms.

2. What type of bonding holds silicon and oxygen atoms together in silicon dioxide?

Strong covalent bonds.

3. Why does silicon dioxide have a high melting point?

Because many strong covalent bonds throughout the giant lattice require a lot of energy to break.

4. Is silicon dioxide soluble in water? Explain.

No, it is insoluble because the strong covalent bonds are not broken by water molecules.

Complete revision guide 4 of 4

Similarities in Properties Between Diamond and Silicon Dioxide Related to Their Structures

Diamond and silicon dioxide (SiO₂) both possess giant covalent structures with tetrahedral bonding, which accounts for their shared properties such as high melting points, hardness, and electrical insulating behaviour.

Syllabus source

Section 3, Topic 2.6, page 14, objective 2.6.4

Open source document ↗

What you should be able to do

  • ✓Describe the giant covalent structures of diamond and silicon dioxide.
  • ✓Explain how the tetrahedral bonding in both substances influences their physical properties.
  • ✓Compare the melting points, hardness, and electrical conductivity of diamond and silicon dioxide.
  • ✓Understand why both substances are poor conductors of electricity despite their strong covalent bonds.
1

Giant Covalent Structures of Diamond and Silicon Dioxide

Diamond is a form of carbon where each carbon atom is covalently bonded to four other carbon atoms in a three-dimensional tetrahedral lattice. This creates a giant covalent structure extending throughout the crystal.

Silicon dioxide (SiO₂), commonly found as quartz, consists of silicon atoms each covalently bonded to four oxygen atoms in a tetrahedral arrangement. Each oxygen atom bridges between two silicon atoms, forming a continuous giant covalent network.

Both structures are giant covalent lattices with strong covalent bonds extending in all directions, resulting in very stable and rigid frameworks.

  • Diamond: each C atom bonded to 4 C atoms tetrahedrally.
  • SiO₂: each Si atom bonded to 4 O atoms tetrahedrally; each O bridges two Si atoms.
  • Both form extensive 3D networks of strong covalent bonds.
2

Tetrahedral Bonding and Its Effect on Properties

The tetrahedral bonding in both diamond and silicon dioxide means that atoms are held in fixed positions by strong covalent bonds in all directions. This rigidity makes the structures very hard and gives them high melting points.

Because the bonding involves shared pairs of electrons localized between atoms, there are no free electrons or ions to carry charge, making both substances electrical insulators.

The strong covalent bonds require large amounts of energy to break, explaining the high melting points observed for both materials.

  • Strong covalent bonds in tetrahedral arrangement.
  • High hardness due to rigid 3D lattice.
  • No free electrons or ions → electrical insulators.
  • High melting points due to energy needed to break bonds.
3

Melting Points and Hardness

Diamond has an extremely high melting point around 3550 °C because breaking the giant covalent lattice requires breaking many strong C–C covalent bonds.

Silicon dioxide melts at about 1710 °C, also very high due to the strong Si–O covalent bonds in its lattice.

Both materials are very hard; diamond is the hardest known natural substance due to the strong and rigid C–C bonds, while silicon dioxide is also hard but less so than diamond because of differences in bond strength and lattice structure.

  • Diamond melting point ≈ 3550 °C; SiO₂ melting point ≈ 1710 °C.
  • Both are very hard solids; diamond is harder than SiO₂.
  • High melting points arise from strong covalent bonds throughout the lattice.
4

Electrical Conductivity

Neither diamond nor silicon dioxide conducts electricity because their electrons are all involved in covalent bonds and are not free to move.

In diamond, all four valence electrons of carbon form covalent bonds, leaving no free electrons or ions.

In silicon dioxide, the electrons are shared in Si–O bonds, and there are no mobile charged particles to carry current.

  • No free electrons or ions → poor electrical conductivity.
  • Diamond and SiO₂ are electrical insulators.
  • Covalent bonding localizes electrons, preventing charge flow.

At-a-glance summary

Comparison table

PropertyDiamondSilicon Dioxide (SiO₂)Explanation/Reason
StructureGiant covalent lattice of carbon atoms tetrahedrally bondedGiant covalent lattice of silicon atoms tetrahedrally bonded to oxygen atomsBoth have 3D networks with strong covalent bonds
Melting Point~3550 °C~1710 °CHigh due to strong covalent bonds; diamond’s C–C bonds stronger than Si–O bonds
HardnessExtremely hard (hardest natural substance)Hard but less than diamondRigid tetrahedral bonding in both; diamond’s uniform C–C bonds give greater hardness
Electrical ConductivityNon-conductorNon-conductorNo free electrons or ions in either structure

Active recall

Quick check

1. What type of bonding holds atoms together in diamond and silicon dioxide?

Strong covalent bonds forming a giant covalent lattice.

2. Why do diamond and silicon dioxide have high melting points?

Because a large amount of energy is needed to break the many strong covalent bonds in their giant covalent structures.

3. Explain why diamond does not conduct electricity.

All valence electrons in diamond are involved in covalent bonds, so there are no free electrons to carry electric charge.

4. How is the structure of silicon dioxide arranged?

Each silicon atom is covalently bonded to four oxygen atoms in a tetrahedral arrangement, with oxygen atoms bridging between silicon atoms to form a giant covalent network.

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