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Magnitude of a vector Revision Notes

Cambridge IGCSE revision notes for Magnitude of a vector.

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Magnitude of a vector

CambridgeIGCSEMathematicsExtended Transformations and vectors

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Calculating the Size (Magnitude) of a Vector

This note explains how to determine the magnitude of a vector, represented by vertical bars such as |AB|, by using coordinate geometry and the distance formula. It covers the concept of vector magnitude as the length between two points, the application of the distance formula, and includes worked examples and exam-focused advice.

Syllabus source

Section 3, Topic E7.3, page 53, objective E7.3.1

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What you should be able to do

  • ✓Understand that the magnitude of a vector represents its length.
  • ✓Learn to denote vector magnitude using vertical bars, e.g., |AB|.
  • ✓Apply the distance formula to calculate the magnitude of a vector given coordinates.
  • ✓Recognise that magnitude is always a non-negative value.
1

What is the Magnitude of a Vector?

A vector is a quantity that has both direction and size (magnitude). The magnitude of a vector is the length of the line segment representing it, regardless of its direction. For example, if vector AB starts at point A and ends at point B, the magnitude is the distance from A to B.

The magnitude is denoted by vertical bars around the vector symbol, such as |AB|, which reads as 'the magnitude of vector AB.' This notation emphasises that we are interested in the size, not the direction, of the vector.

  • Magnitude represents the length of the vector.
  • Denoted by vertical bars: |AB| means the size of vector AB.
  • Magnitude is always zero or positive.
2

Using Coordinates to Find Vector Magnitude

When points A and B are given in a coordinate plane, their coordinates allow us to calculate the magnitude of vector AB precisely. Suppose A has coordinates (x₁, y₁) and B has coordinates (x₂, y₂). The vector AB points from A to B.

The magnitude |AB| is the straight-line distance between these two points. This distance can be found using the distance formula derived from the Pythagorean theorem.

  • Identify coordinates of points A and B.
  • Use the distance formula to find |AB|.
  • Magnitude is the length of the segment AB.
3

The Distance Formula and Calculation

The distance formula between two points (x₁, y₁) and (x₂, y₂) is:

\[ |AB| = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] This formula calculates the length of the hypotenuse of a right-angled triangle formed by the horizontal and vertical differences between the points.

To calculate the magnitude, subtract the x-coordinates and y-coordinates, square these differences, add them, and then take the square root of the sum.

  • Calculate horizontal difference: (x₂ - x₁).
  • Calculate vertical difference: (y₂ - y₁).
  • Square both differences and add.
  • Take the square root to find |AB|.
4

Worked Example

Find the magnitude of vector AB where A is at (2, 3) and B is at (7, 11).

Step 1: Calculate the differences: x₂ - x₁ = 7 - 2 = 5, y₂ - y₁ = 11 - 3 = 8.

Step 2: Square the differences: 5² = 25, 8² = 64, sum = 25 + 64 = 89, Step 3: Take the square root: \( \sqrt{89} \approx 9.43 \). Therefore, |AB| ≈ 9.43 units.

  • Use coordinates (2, 3) and (7, 11).
  • Calculate differences: 5 and 8.
  • Sum of squares: 89.
  • Magnitude: approximately 9.43 units.
5

Key Points for Exam Success

Always write the magnitude with vertical bars, for example |AB|, to show you are calculating the size of the vector.

Show all steps clearly: state coordinates, calculate differences, square, sum, and square root.

Remember magnitude cannot be negative; if you get a negative value, check your calculations carefully as the square root is always non-negative in this context.

  • Use correct notation: |AB| for magnitude.
  • Show full calculation steps.
  • Magnitude is always ≥ 0.

At-a-glance summary

Comparison table

StepDetailExampleExam Use
Identify pointsFind coordinates of vector start and end pointsA(2,3), B(7,11)Always label points clearly
Calculate differencesSubtract coordinates: x₂ - x₁ and y₂ - y₁5 and 8Write differences explicitly
Square and addSquare differences and sum: 5² + 8² = 25 + 64 = 89Sum is 89Show intermediate sums
Square rootTake √89 ≈ 9.43Magnitude ≈ 9.43 unitsFinal answer with units

Active recall

Quick check

1. If A is at (1, 2) and B is at (4, 6), what is |AB|?

Calculate differences: 4 - 1 = 3, 6 - 2 = 4; square and add: 3² + 4² = 9 + 16 = 25; square root: √25 = 5; so |AB| = 5.

2. What does the notation |AB| represent?

It represents the magnitude (length) of vector AB, the distance between points A and B.

3. Can the magnitude of a vector be negative?

No, magnitude is always zero or positive because it represents length.

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